英语翻译in a two-digit number,the units digit is greater than the tens digit by 3 If tens digit and the units digit of the number are interchanged,the sum of the number obtained and the original number is 121.FIND THE TWO NUMBERS

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英语翻译in a two-digit number,the units digit is greater than the tens digit by 3 If tens digit and the units digit of the number are interchanged,the sum of the number obtained and the original number is 121.FIND THE TWO NUMBERS
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英语翻译in a two-digit number,the units digit is greater than the tens digit by 3 If tens digit and the units digit of the number are interchanged,the sum of the number obtained and the original number is 121.FIND THE TWO NUMBERS
英语翻译
in a two-digit number,the units digit is greater than the tens digit by 3 If tens digit and the units digit of the number are interchanged,the sum of the number obtained and the original number is 121.FIND THE TWO NUMBERS

英语翻译in a two-digit number,the units digit is greater than the tens digit by 3 If tens digit and the units digit of the number are interchanged,the sum of the number obtained and the original number is 121.FIND THE TWO NUMBERS
Suppose the tens digit is x,the units digit is x+3,the original number is x*10+(x+3),the obtained number is (x+3)*10+x;
(x+3)*10+x+x*10+(x+3)=121,calculate x=4
the original number is 47,the obtained number is 74
题目：已知一个2位数,个位上的数字比十位上的数字大3,如果将十位和个位数字调换,则新组成的这个数字和原数字之和为121,求这2个数字分别为多少.

个位大于十位3。
交换后，两个数字相加是121.
大了3相加末尾要是1，那么很容易知道是4和7。
原数就是47.

翻译 ：一个两位数，个位数比十位数大3，如果将个位与十位交换，所得到的数与原来的数相加，和等于121，求原来的数。
设原来的数的个位是x，十位数是y，则原来的数=10*y+x，根据条件，x-y=3
个位与十位交换后的数=10*x+y，则根据条件 (10*y+x)+(10*x+y)=121
结合这两个方程，可以得到 x=7 y=4
所以原来的数是47
...

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翻译 ：一个两位数，个位数比十位数大3，如果将个位与十位交换，所得到的数与原来的数相加，和等于121，求原来的数。
设原来的数的个位是x，十位数是y，则原来的数=10*y+x，根据条件，x-y=3
个位与十位交换后的数=10*x+y，则根据条件 (10*y+x)+(10*x+y)=121
结合这两个方程，可以得到 x=7 y=4
所以原来的数是47
英文步骤：
Suppose the units digit number is x and the tens digit is y
then the original number is 10*y+x and x-y=3
the interchanged number is 10*x+y
so (10*y+x)+(10*x+y)=121
x=7 y=4
the original number is 47

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翻译：有一个两位数，个位数比十位数大3，个位数和十位数交换所得数加原数等于121，
求这个数？
设十位数为x，则个位数为x+3，依题设，得 [10x+(x+3)]+[10(x+3)+x]=121
x=4 x+3=7 这个数为47

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