在平行四边形ABCD中,过点C作CE⊥CD交AD于点E,将线段EC绕点E逆时针旋转90°得到线段EF(如图1)(1)在图1中画图探究:①当P为射线CD上任意一点(P1不与C重合)时,连接EP1;绕点E逆时针旋转90°
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/09 00:20:09
![在平行四边形ABCD中,过点C作CE⊥CD交AD于点E,将线段EC绕点E逆时针旋转90°得到线段EF(如图1)(1)在图1中画图探究:①当P为射线CD上任意一点(P1不与C重合)时,连接EP1;绕点E逆时针旋转90°](/uploads/image/z/3976766-62-6.jpg?t=%E5%9C%A8%E5%B9%B3%E8%A1%8C%E5%9B%9B%E8%BE%B9%E5%BD%A2ABCD%E4%B8%AD%2C%E8%BF%87%E7%82%B9C%E4%BD%9CCE%E2%8A%A5CD%E4%BA%A4AD%E4%BA%8E%E7%82%B9E%2C%E5%B0%86%E7%BA%BF%E6%AE%B5EC%E7%BB%95%E7%82%B9E%E9%80%86%E6%97%B6%E9%92%88%E6%97%8B%E8%BD%AC90%C2%B0%E5%BE%97%E5%88%B0%E7%BA%BF%E6%AE%B5EF%EF%BC%88%E5%A6%82%E5%9B%BE1%EF%BC%89%EF%BC%881%EF%BC%89%E5%9C%A8%E5%9B%BE1%E4%B8%AD%E7%94%BB%E5%9B%BE%E6%8E%A2%E7%A9%B6%EF%BC%9A%E2%91%A0%E5%BD%93P%E4%B8%BA%E5%B0%84%E7%BA%BFCD%E4%B8%8A%E4%BB%BB%E6%84%8F%E4%B8%80%E7%82%B9%EF%BC%88P1%E4%B8%8D%E4%B8%8EC%E9%87%8D%E5%90%88%EF%BC%89%E6%97%B6%2C%E8%BF%9E%E6%8E%A5EP1%EF%BC%9B%E7%BB%95%E7%82%B9E%E9%80%86%E6%97%B6%E9%92%88%E6%97%8B%E8%BD%AC90%C2%B0)
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