已知:角ABC =角DBE=90°,DB =BE,AB=BC已知:角ABC =角DBE=90°,DB =BE,AB=BC (1)求证:AD=CE,AD垂直CE; (2)若三角形DBE 绕点B旋转到三角形ABC外部,其他条件不变,则(1)中结论是否仍成立?请证
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![已知:角ABC =角DBE=90°,DB =BE,AB=BC已知:角ABC =角DBE=90°,DB =BE,AB=BC (1)求证:AD=CE,AD垂直CE; (2)若三角形DBE 绕点B旋转到三角形ABC外部,其他条件不变,则(1)中结论是否仍成立?请证](/uploads/image/z/3977004-12-4.jpg?t=%E5%B7%B2%E7%9F%A5%EF%BC%9A%E8%A7%92ABC+%3D%E8%A7%92DBE%3D90%C2%B0%2CDB+%3DBE%2CAB%3DBC%E5%B7%B2%E7%9F%A5%EF%BC%9A%E8%A7%92ABC+%3D%E8%A7%92DBE%3D90%C2%B0%2CDB+%3DBE%2CAB%3DBC++++++++++%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9AAD%3DCE%2CAD%E5%9E%82%E7%9B%B4CE%3B+++++%EF%BC%882%EF%BC%89%E8%8B%A5%E4%B8%89%E8%A7%92%E5%BD%A2DBE+%E7%BB%95%E7%82%B9B%E6%97%8B%E8%BD%AC%E5%88%B0%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E5%A4%96%E9%83%A8%2C%E5%85%B6%E4%BB%96%E6%9D%A1%E4%BB%B6%E4%B8%8D%E5%8F%98%2C%E5%88%99%EF%BC%881%EF%BC%89%E4%B8%AD%E7%BB%93%E8%AE%BA%E6%98%AF%E5%90%A6%E4%BB%8D%E6%88%90%E7%AB%8B%3F%E8%AF%B7%E8%AF%81)
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