1^(1/2)+2^(1/2)+3^(1/2)+……+n^(1/2)有公式吗?y=1/x求和呢?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/14 06:54:55
![1^(1/2)+2^(1/2)+3^(1/2)+……+n^(1/2)有公式吗?y=1/x求和呢?](/uploads/image/z/3977581-13-1.jpg?t=1%5E%EF%BC%881%2F2%EF%BC%89%2B2%5E%EF%BC%881%2F2%EF%BC%89%2B3%5E%EF%BC%881%2F2%EF%BC%89%2B%E2%80%A6%E2%80%A6%2Bn%5E%EF%BC%881%2F2%EF%BC%89%E6%9C%89%E5%85%AC%E5%BC%8F%E5%90%97%3Fy%3D1%2Fx%E6%B1%82%E5%92%8C%E5%91%A2%3F)
x)3{PNm#$1Q2 C=u=O'L5ԯx餞$X;7J_$35)Q/)13T/9?W@F 1 Ɨd
1^(1/2)+2^(1/2)+3^(1/2)+……+n^(1/2)有公式吗?y=1/x求和呢?
1^(1/2)+2^(1/2)+3^(1/2)+……+n^(1/2)有公式吗?y=1/x求和呢?
1^(1/2)+2^(1/2)+3^(1/2)+……+n^(1/2)有公式吗?y=1/x求和呢?
http://tieba.baidu.com/p/2238792629
(1-1/2^2)(1-1/3^2)K(1-1/10^2)
(1-1/2^2)(1-1/3^2)K(1-1/10^2)
(1/2+1/3+...+1/2004)(1+1/2+1/3+...+1/2003)-(1+1/2+1/3+...+1/2004)(1/2+1/3+...+1/2003)
(1/3m-1/2)^2
(1/1+2)+(1/1+2+3)+…+(1/1+2+3…+2000)
(1/2+1/3+...+1/2007)*(1+1/2+1/3+...+1/2006)-(1+1/2+1/3+...+/2007)*(1/2+1/3+...+1/2006)
200*(1-1/2)*(1-1/3)*(1-1/4)*.*(1-1/100)
1、1、2、3、5、( )、( ).
计算:(1/2+1/3+...+1/2011)*(1+1/2+1/3+...+1/2010)-(1+1/2+1/3+...+1/2011)*(1/2+1/3+...+1/2010)
计算(1-1/2-1/3-...-1/2010)*(1/2+1/3+..+1/2011)-(1-1/2-1/3-...-1/2011)*(1/2+1/3+...+1/2010)
计算:(-1)-[1-(1-1/2*1/3)]*6
计算!(-1)-[1-(1-1/2*1/3)]*6
1/1+1/(1+2)+1/(1+2+3)+.+1/(1+2+3+.+100)不用计算器
-1/2+(-1/6)-(-1/4)-2/3
巧算(奥数题)问:(1+1/2)×(1-1/2)×(1+1/3)×(1-1/3)×...(1+1/99)×(1-1/99)
2000*(1-1/2*)*(1-1/3)*...*(1-1999)*(1-1/2000)
(1-2/1)*(1-3/1)*(1-4/1)*.*(1-2007/1)*(1-2008/1)
(1/2014-1)(1/2013-1)(1-2012-1)...(1/3-1)(1/2-1)