log7[log3(log2x)]=log5tan45°则x^(-1/2)=?

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/06 07:09:31
log7[log3(log2x)]=log5tan45°则x^(-1/2)=?
x)O7@¨B3H$晘cfEMR>~`z lȱHjC[N# aBF `NYfc

log7[log3(log2x)]=log5tan45°则x^(-1/2)=?
log7[log3(log2x)]=log5tan45°
则x^(-1/2)=?

log7[log3(log2x)]=log5tan45°则x^(-1/2)=?
log5tan45°
=log5 1=0
log7[log3(log2x)]=0
log3(log2x)]=1
log2 x=3
x=8
x^(-1/2)=8^(-1/2)=√2/4