解方程:(一定要有过程和答案,)①y- [(y-1)/2 ]=2- [(y+3)/5 ]②(x/5)- [(3-2x)/2 ]=x③ [(2y+1)/4 ]+[(10y+1)/ 6 ]=1- [(1-2y)/3 ]④ [(x-2)/5 ] -[(x+3)/10 ]-[ (2x-5)/3 ]+3=0
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/05 07:43:33
![解方程:(一定要有过程和答案,)①y- [(y-1)/2 ]=2- [(y+3)/5 ]②(x/5)- [(3-2x)/2 ]=x③ [(2y+1)/4 ]+[(10y+1)/ 6 ]=1- [(1-2y)/3 ]④ [(x-2)/5 ] -[(x+3)/10 ]-[ (2x-5)/3 ]+3=0](/uploads/image/z/3997854-54-4.jpg?t=%E8%A7%A3%E6%96%B9%E7%A8%8B%EF%BC%9A%EF%BC%88%E4%B8%80%E5%AE%9A%E8%A6%81%E6%9C%89%E8%BF%87%E7%A8%8B%E5%92%8C%E7%AD%94%E6%A1%88%2C%EF%BC%89%E2%91%A0y%EF%BC%8D+%5B%EF%BC%88y%EF%BC%8D1%EF%BC%89%2F2+%5D%3D2%EF%BC%8D+%5B%EF%BC%88y%2B3%EF%BC%89%2F5+%5D%E2%91%A1%EF%BC%88x%2F5%EF%BC%89%EF%BC%8D+%5B%EF%BC%883%EF%BC%8D2x%EF%BC%89%2F2+%5D%3Dx%E2%91%A2+%5B%EF%BC%882y%2B1%EF%BC%89%2F4+%5D%2B%5B%EF%BC%8810y%2B1%EF%BC%89%2F+6+%5D%3D1-+%5B%EF%BC%881%EF%BC%8D2y%EF%BC%89%2F3+%5D%E2%91%A3+%5B%EF%BC%88x%EF%BC%8D2%EF%BC%89%2F5+%5D+%EF%BC%8D%5B%EF%BC%88x%2B3%EF%BC%89%2F10+%5D%EF%BC%8D%5B+%EF%BC%882x%EF%BC%8D5%EF%BC%89%2F3+%5D%2B3%3D0)
解方程:(一定要有过程和答案,)①y- [(y-1)/2 ]=2- [(y+3)/5 ]②(x/5)- [(3-2x)/2 ]=x③ [(2y+1)/4 ]+[(10y+1)/ 6 ]=1- [(1-2y)/3 ]④ [(x-2)/5 ] -[(x+3)/10 ]-[ (2x-5)/3 ]+3=0
解方程:(一定要有过程和答案,)
①y- [(y-1)/2 ]=2- [(y+3)/5 ]
②(x/5)- [(3-2x)/2 ]=x
③ [(2y+1)/4 ]+[(10y+1)/ 6 ]=1- [(1-2y)/3 ]
④ [(x-2)/5 ] -[(x+3)/10 ]-[ (2x-5)/3 ]+3=0
解方程:(一定要有过程和答案,)①y- [(y-1)/2 ]=2- [(y+3)/5 ]②(x/5)- [(3-2x)/2 ]=x③ [(2y+1)/4 ]+[(10y+1)/ 6 ]=1- [(1-2y)/3 ]④ [(x-2)/5 ] -[(x+3)/10 ]-[ (2x-5)/3 ]+3=0
①y- [(y-1)/2 ]=2- [(y+3)/5 ]
去分母得
10y-5(y-1)=20-2(y+3)
去括号得
10y-5y+5=20-2y-6
移项、合并同类项得
7y=9
系数化成1得
y=9/7
②(x/5)- [(3-2x)/2 ]=x
去分母得
2x-5(3-2x)=10x
去括号得
2x-15+10x=10x
移项、合并同类项得
2x=15
系数化成1得
x=7.5
③ [(2y+1)/4 ]+[(10y+1)/ 6 ]=1- [(1-2y)/3 ]
去分母得
3(2y+1)+2(10y+1)=12-4(1-2y)
去括号得
6y+3+20y+2=12-4+8y
移项、合并同类项得
18y=3
系数化成1得
y=1/6
④ [(x-2)/5 ] -[(x+3)/10 ]-[ (2x-5)/3 ]+3=0
去分母得
6(x-2)-3(x+3)-10(2x-5)+90=0
去括号得
6x-12-3x-9-20x+50+90=0
移项、合并同类项得
-17x=-119
系数化成1得
x=7