cos^2A - cos^2B + sin^2C=2cosA *sinB *sinC证明

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/17 21:02:40
cos^2A - cos^2B + sin^2C=2cosA *sinB *sinC证明
x)K/3rTU33⌜m Z@t~ٌ>"}5ِi^i pvN@3XX3^%x%ecqHh8i;j"Ij .pra"0Mr-#@A9qE3~qAb(

cos^2A - cos^2B + sin^2C=2cosA *sinB *sinC证明
cos^2A - cos^2B + sin^2C=2cosA *sinB *sinC证明

cos^2A - cos^2B + sin^2C=2cosA *sinB *sinC证明
左边=sin(A+B)sin(B-A)+sin²C
=sin(180-C)sin(B-A)+sin²C
=sinCsin(B-A)+sin²C
=sinC[sin(B-A)+sinC]
=sinC[sin(B-A)+sin(B+A)]
=sinC(sinBcosA-cosBsinA+sinBcosA+cosBsinA)
=sinC*2sinBcosA=右边
命题得证