等差数列{an}中,a10=30,a20=50,则通式an=

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等差数列{an}中,a10=30,a20=50,则通式an=
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等差数列{an}中,a10=30,a20=50,则通式an=
等差数列{an}中,a10=30,a20=50,则通式an=

等差数列{an}中,a10=30,a20=50,则通式an=
a10=a1+9d
a20=a1+19d
d=(50-30)/(19-9)
=2
a1=a10-9d
=30-18
=12
an=a1+(n-1)d
=12+2n-2
=2n+10

a10=30,a20=50
d=(a20-a10)/(20-10)=(50-30)/10=2
a1=a10-9*d=30-9*2=12

通式 an=12+2n

d=(a20-a10)/(20-10)=2
an=a10+(n-10)d
=30+2(n-10)
=2n+10