作业帮1 不等式|x+2|+|x-1|小于a 解集是空集.则a的取值范围2 对任意a b∈R 都有f(a+b)=f(a)+f(b)-1 当x大于0时 f(x)大于1.求证:f(x)是R上增函数.若f(4)=5 解不等式f(3m^2-m-2)小于33 函数y=-x^2+ax-a/4+1/2,在区间[0,1]上最
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![1 不等式|x+2|+|x-1|小于a 解集是空集.则a的取值范围2 对任意a b∈R 都有f(a+b)=f(a)+f(b)-1 当x大于0时 f(x)大于1.求证:f(x)是R上增函数.若f(4)=5 解不等式f(3m^2-m-2)小于33 函数y=-x^2+ax-a/4+1/2,在区间[0,1]上最](/uploads/image/z/405812-20-2.jpg?t=1+%E4%B8%8D%E7%AD%89%E5%BC%8F%7Cx%2B2%7C%2B%7Cx-1%7C%E5%B0%8F%E4%BA%8Ea+%E8%A7%A3%E9%9B%86%E6%98%AF%E7%A9%BA%E9%9B%86.%E5%88%99a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B42+%E5%AF%B9%E4%BB%BB%E6%84%8Fa+b%E2%88%88R+%E9%83%BD%E6%9C%89f%28a%2Bb%29%3Df%28a%29%2Bf%28b%29-1+%E5%BD%93x%E5%A4%A7%E4%BA%8E0%E6%97%B6+f%28x%29%E5%A4%A7%E4%BA%8E1.%E6%B1%82%E8%AF%81%3Af%28x%29%E6%98%AFR%E4%B8%8A%E5%A2%9E%E5%87%BD%E6%95%B0.%E8%8B%A5f%284%29%3D5+%E8%A7%A3%E4%B8%8D%E7%AD%89%E5%BC%8Ff%283m%5E2-m-2%29%E5%B0%8F%E4%BA%8E33+%E5%87%BD%E6%95%B0y%3D-x%5E2%2Bax-a%2F4%2B1%2F2%2C%E5%9C%A8%E5%8C%BA%E9%97%B4%5B0%2C1%5D%E4%B8%8A%E6%9C%80)
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