p:25x^2-10x+1-a^2(a>0)和条件q:1/(2x^2-3x+1)>0,构造命题"若p则q",并使构造的原命题为真命题,逆命题为假命题,求实数a 的取值范围p:25x^2-10x+1-a^2>0(a>0)
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/18 06:47:03
![p:25x^2-10x+1-a^2(a>0)和条件q:1/(2x^2-3x+1)>0,构造命题](/uploads/image/z/4059926-62-6.jpg?t=p%3A25x%5E2-10x%2B1-a%5E2%28a%3E0%29%E5%92%8C%E6%9D%A1%E4%BB%B6q%3A1%2F%282x%5E2-3x%2B1%29%3E0%2C%E6%9E%84%E9%80%A0%E5%91%BD%E9%A2%98%22%E8%8B%A5p%E5%88%99q%22%2C%E5%B9%B6%E4%BD%BF%E6%9E%84%E9%80%A0%E7%9A%84%E5%8E%9F%E5%91%BD%E9%A2%98%E4%B8%BA%E7%9C%9F%E5%91%BD%E9%A2%98%2C%E9%80%86%E5%91%BD%E9%A2%98%E4%B8%BA%E5%81%87%E5%91%BD%E9%A2%98%2C%E6%B1%82%E5%AE%9E%E6%95%B0a+%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4p%3A25x%5E2-10x%2B1-a%5E2%3E0%28a%3E0%29)
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