若sinB=m*sin(2A+B),其中M不为1,角A不等于90度的倍数,求证:tan(A+B)=(1+m)/(1-m)*tanA麻烦把过程写下来
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![若sinB=m*sin(2A+B),其中M不为1,角A不等于90度的倍数,求证:tan(A+B)=(1+m)/(1-m)*tanA麻烦把过程写下来](/uploads/image/z/4114546-34-6.jpg?t=%E8%8B%A5sinB%3Dm%2Asin%282A%2BB%29%2C%E5%85%B6%E4%B8%ADM%E4%B8%8D%E4%B8%BA1%2C%E8%A7%92A%E4%B8%8D%E7%AD%89%E4%BA%8E90%E5%BA%A6%E7%9A%84%E5%80%8D%E6%95%B0%2C%E6%B1%82%E8%AF%81%3Atan%28A%2BB%29%3D%281%2Bm%29%2F%281-m%29%2AtanA%E9%BA%BB%E7%83%A6%E6%8A%8A%E8%BF%87%E7%A8%8B%E5%86%99%E4%B8%8B%E6%9D%A5)
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若sinB=m*sin(2A+B),其中M不为1,角A不等于90度的倍数,求证:tan(A+B)=(1+m)/(1-m)*tanA麻烦把过程写下来
若sinB=m*sin(2A+B),其中M不为1,角A不等于90度的倍数,求证:tan(A+B)=(1+m)/(1-m)*tanA
麻烦把过程写下来
若sinB=m*sin(2A+B),其中M不为1,角A不等于90度的倍数,求证:tan(A+B)=(1+m)/(1-m)*tanA麻烦把过程写下来
sinB=m*sin(2A+B)
m=sinB/sin(2A+B)
1+m=[sin(2A+B)+sinB]/sin(2A+B)=2[sin(A+B)cosA]/sin(2A+B)
1-m=[sin(2A+B)-sinB]/sin(2A+B)=2[cos(A+B)sinA]/sin(2A+B)
(1+m)/(1-m)
=[sin(A+B)cosA]/[cos(A+B)sinA]
=tan(A+B)/tanA
tan(A+B)=(1+m)/(1-m)*tanA
若sinB=m*sin(2A+B),其中M不为1,角A不等于90度的倍数,求证:tan(A+B)=(1+m)/(1-m)*tanA麻烦把过程写下来
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