证明 半角公式1)cosα/(1-sinα)=(cotα/2+1)/(cotα/2-1)2)(1+sinα)/(1-sinα)=tan^2(α/2+45°)3)cos^4x=(1/2+1/2cos2x)^2
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![证明 半角公式1)cosα/(1-sinα)=(cotα/2+1)/(cotα/2-1)2)(1+sinα)/(1-sinα)=tan^2(α/2+45°)3)cos^4x=(1/2+1/2cos2x)^2](/uploads/image/z/4204269-45-9.jpg?t=%E8%AF%81%E6%98%8E+%E5%8D%8A%E8%A7%92%E5%85%AC%E5%BC%8F1%EF%BC%89cos%CE%B1%2F%281-sin%CE%B1%29%3D%28cot%CE%B1%2F2%2B1%29%2F%28cot%CE%B1%2F2-1%292%EF%BC%89%EF%BC%881%2Bsin%CE%B1%EF%BC%89%2F%EF%BC%881-sin%CE%B1%EF%BC%89%3Dtan%5E2%28%CE%B1%2F2%2B45%C2%B0%293%EF%BC%89cos%5E4x%3D%281%2F2%2B1%2F2cos2x%29%5E2)
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