double Hsmax=0.594+2.29*Math.Pow((-Math.Log10(1-Math.Exp(1/56*Math.Log10(0.1)))),0.722);这个表达式求的结果是无穷大,什么原因?

double Hsmax=0.594+2.29*Math.Pow((-Math.Log10(1-Math.Exp(1/56*Math.Log10(0.1)))),0.722);这个表达式求的结果是无穷大,什么原因? double pow(double x,double y) C语言#include#includeint main(){double pn[5],t[5],p0=10000;t[0]=double pow(double 1.50,double 2.0);pn[0]=p0*t[0];t[1]=double pow(double 4.10,double 8.0);pn[1]=p0*t[1];t[2]=double pow(double 4.30,double 4.0);pn[2]=p0*t[ double ** p=new double* int b(double l,double r) { double a; aint b(double l,double r){double a;a=(l+r)/2;if(a*a-6>0) b(l,a);else if(a*a-6 #includeusing namespace std;#define PI 314159double area(double radius=0);double area(double a,double b);double area(double a,double b,double h);double area(double a,double b,double c,int);int main(){cout #include double fun( int m ){double t = 1.0;int i;for( i = 2; i double max=Double.MIN_VALUE什么意思 double **Maze = new double *[8] 【c++】现有三个函数（1）double Add(double a) (2)double Add(double a,double b) (3)……如题,(3) int Add(double a,double b,double c=0)现在对Add函数进行调用,编译出现错误的是A.Add(3) B.Add(3.3,3.4) C.Add(2.3,3.1,3.2) D.Add(3 double* xyz_scale = 0; double double double double double double double double