谁能解释一道基础物理题Determine the stopping distances for an automobile with an initial velocity of 90km/h and human reaction time of 1.0s for an acceleration -4m/s^2.翻译:一辆摩托车在以 90km/h 的速度在高速公路上奔跑
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![谁能解释一道基础物理题Determine the stopping distances for an automobile with an initial velocity of 90km/h and human reaction time of 1.0s for an acceleration -4m/s^2.翻译:一辆摩托车在以 90km/h 的速度在高速公路上奔跑](/uploads/image/z/4307640-24-0.jpg?t=%E8%B0%81%E8%83%BD%E8%A7%A3%E9%87%8A%E4%B8%80%E9%81%93%E5%9F%BA%E7%A1%80%E7%89%A9%E7%90%86%E9%A2%98Determine+the+stopping+distances+for+an+automobile+with+an+initial+velocity+of+90km%2Fh+and+human+reaction+time+of+1.0s+for+an+acceleration+-4m%2Fs%5E2.%E7%BF%BB%E8%AF%91%EF%BC%9A%E4%B8%80%E8%BE%86%E6%91%A9%E6%89%98%E8%BD%A6%E5%9C%A8%E4%BB%A5+90km%2Fh+%E7%9A%84%E9%80%9F%E5%BA%A6%E5%9C%A8%E9%AB%98%E9%80%9F%E5%85%AC%E8%B7%AF%E4%B8%8A%E5%A5%94%E8%B7%91)
谁能解释一道基础物理题Determine the stopping distances for an automobile with an initial velocity of 90km/h and human reaction time of 1.0s for an acceleration -4m/s^2.翻译:一辆摩托车在以 90km/h 的速度在高速公路上奔跑
谁能解释一道基础物理题
Determine the stopping distances for an automobile with an initial velocity of 90km/h and human reaction time of 1.0s for an acceleration -4m/s^2.
翻译:一辆摩托车在以 90km/h 的速度在高速公路上奔跑着,如果该摩托车以 -4m/s^2的速度加速的话,假设人的反应速度为 1s 的话大约该摩托车在减速后还要滑行多长距离?
答案是103米,包括公式,单位还有为什么?
一楼的大大,你刚才的确回答过了,只不过偶太笨,没搞懂而已 - -||。
谁能解释一道基础物理题Determine the stopping distances for an automobile with an initial velocity of 90km/h and human reaction time of 1.0s for an acceleration -4m/s^2.翻译:一辆摩托车在以 90km/h 的速度在高速公路上奔跑
90km/h=25m/s,他的速度换算成米每秒
25/4=6.25s; 车在刹车后还需要6.25秒才能停止,期间的平均速度为(25-0)/2
距离L=平均速度*行驶时间+反应的1秒要行驶的路程
25*1+25*6.25/2=103.125
好像刚才问过一回了。
25*6.25/2+25=103.125(图解法)