已知实数a,b满足5a2+2001a+9=0,9b2+2001b+5=0,且ab不等于1,则a/b的值为
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![已知实数a,b满足5a2+2001a+9=0,9b2+2001b+5=0,且ab不等于1,则a/b的值为](/uploads/image/z/4322090-2-0.jpg?t=%E5%B7%B2%E7%9F%A5%E5%AE%9E%E6%95%B0a%2Cb%E6%BB%A1%E8%B6%B35a2%2B2001a%2B9%3D0%2C9b2%2B2001b%2B5%3D0%2C%E4%B8%94ab%E4%B8%8D%E7%AD%89%E4%BA%8E1%2C%E5%88%99a%2Fb%E7%9A%84%E5%80%BC%E4%B8%BA)
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已知实数a,b满足5a2+2001a+9=0,9b2+2001b+5=0,且ab不等于1,则a/b的值为
已知实数a,b满足5a2+2001a+9=0,9b2+2001b+5=0,且ab不等于1,则a/b的值为
已知实数a,b满足5a2+2001a+9=0,9b2+2001b+5=0,且ab不等于1,则a/b的值为
∵5a^2+2001a+9=0, 9b^2+2001b+5=0,
∴5a+9/a=2001, 9b+5/b=2001,两式相减,得:(5a-9b)+(9/a-5/b)=0
∴(5a-9b)-(5a-9b)/ab=0,∵ab≠1,∴5a-9b=0,得:a/b=9/5.
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