求证6^a/36^(a+1)+1≤5/6-b+b²/3
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求证6^a/36^(a+1)+1≤5/6-b+b²/3
求证6^a/36^(a+1)+1≤5/6-b+b²/3
求证6^a/36^(a+1)+1≤5/6-b+b²/3
5/6-b+b^2/3=(1/3)(b-3/2)^2+1/12,设x=6^a,则x>0,36^(a+1)=36x^2,
∴原式x/(36x+1)