谁能帮忙解下这个很难的微分方程,英文的, A second order homogeneous Cauchy-Euler Equation is an equation of the type: Question 1:Assuming a solution in the form y=x^m derive the auxiliary equation for the C-E DE a
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![谁能帮忙解下这个很难的微分方程,英文的, A second order homogeneous Cauchy-Euler Equation is an equation of the type: Question 1:Assuming a solution in the form y=x^m derive the auxiliary equation for the C-E DE a](/uploads/image/z/14342955-51-5.jpg?t=%E8%B0%81%E8%83%BD%E5%B8%AE%E5%BF%99%E8%A7%A3%E4%B8%8B%E8%BF%99%E4%B8%AA%E5%BE%88%E9%9A%BE%E7%9A%84%E5%BE%AE%E5%88%86%E6%96%B9%E7%A8%8B%2C%E8%8B%B1%E6%96%87%E7%9A%84%2C+++++A+second+order+homogeneous+Cauchy-Euler+Equation+is+an+equation+of+the+type%3A++++++++++++++++++Question+1%3AAssuming+a+solution+in+the+form+y%3Dx%5Em+derive+the+auxiliary+equation+for+the+C-E+DE+a)
谁能帮忙解下这个很难的微分方程,英文的, A second order homogeneous Cauchy-Euler Equation is an equation of the type: Question 1:Assuming a solution in the form y=x^m derive the auxiliary equation for the C-E DE a
谁能帮忙解下这个很难的微分方程,英文的,
A second order homogeneous Cauchy-Euler Equation is an equation of the type:
Question 1:Assuming a solution in the form y=x^m derive the auxiliary equation for the C-E DE and give the general solution to the problem.
Question 2:Show that if the roots of theauxiliary equation are complex:m1,2=a+bi or a-bi,the general solution may be written as y(x)=x^a [c1*cos(b*ln(x)+c2*sin(b*lnx)).
谁能帮忙解下这个很难的微分方程,英文的, A second order homogeneous Cauchy-Euler Equation is an equation of the type: Question 1:Assuming a solution in the form y=x^m derive the auxiliary equation for the C-E DE a
个二阶齐次方程柯西欧拉方程的类型:问题1:假设一个解决方案在形式y = x ^ m获得辅助方程为汉英德,给一般的解决问题的办法.问题2:表明,如果theauxiliary方程的根是复杂的:m1,2 = + bi或bi,通常的解决方案可能会写成y(x)= x ^[c1 * cos(b * ln(x)+ c2 *罪(b * lnx)).