求y=sin(2x+π/6)x∈(0,π/3)的值域
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 22:43:02
![求y=sin(2x+π/6)x∈(0,π/3)的值域](/uploads/image/z/4327488-0-8.jpg?t=%E6%B1%82y%3Dsin%282x%2B%CF%80%2F6%29x%E2%88%88%280%2C%CF%80%2F3%29%E7%9A%84%E5%80%BC%E5%9F%9F)
x){Ҷ83OèB|fţ
X
{ΟoTOR;EUBV0!5A)B{%HPH0F 1*0b==ȆӍlP3b6P GR
求y=sin(2x+π/6)x∈(0,π/3)的值域
求y=sin(2x+π/6)x∈(0,π/3)的值域
求y=sin(2x+π/6)x∈(0,π/3)的值域
y=sin(2x+π/6)
x∈(0,π/3)
2x∈(0,2π/3)
2x+π/6∈(π/6,5π/6)
y∈(1/2,1]
x∈(0,π/3)
2x+π/6∈(π/6,5π/6)
则:
y∈(1/2,1]
y=2sin(2x+π/6)x∈[0,π/2],求值域
求y=sin(2x+π/6)x∈(0,π/3)的值域
已知sinx=3/5,x∈(π/2,π),求【sin(x+y)+sin(x-y)】/【cos(x+y)+cos(x-y)】的值
已知y=sin(2x+π/6) 求值域
y=sin(2x+π/6),x∈[π/4,3π/4]求值域
求函数的值域y=sin(2x+π/3),x∈(-π/6,π)
y=sin^2x+sin (π/2-x)+3sin^2(3π/2-x)若tanx=0.5.求y值;若x∈【0,π/2】求y值域
求函数y=sin^4x+cos^4x,x(0,π/6)的最小值
设x∈[0,π],y∈[0,1],试求函数f(x,y)=(2y-1)sinx+(1-y)sin[(1-y)x]的最小值.
求下列函数周期 y=3sin(x/4) x属于Ry=2sin(2x-π/6)
求函数y=2sin(2x+π/6),x∈(-π,0]的单调递减区间
求函数y=sin(2x-π/6)在x∈(0,π/2)上时的值域
求函数y=2sin(2x+π/6),x∈(-π,0]的单调递减区间
求函数y=3-2sin(x+π/6),x∈[0,2π]的值域thankou!
函数y=2sin(π/6-2x)(x∈[0,π])的递增区间是( )求详解,
f(x)=2sin(2x-π/6) 若x属于【0,π】 求y的单调增区间
Excel中画函数图,求x取值和y的公式 y = 2cos3x ,x ∈[0,2π/3 ] y = 3sin(2x + ) ,x∈[-π/6 ,5π/6 ]y = 2cos3x ,x ∈[0,2π/3 ] y = 3sin(2x + ) ,x∈[-π/6 ,5π/6 ]急用
求函数y=sin(π/6-3x),x∈(π/6,π/2]的值域 求详解