(0.1二次方+0.2二次方+0.3二次方+0.4二次方)的二次方除以(0.1三次方+······0.4三次方简算小辈感激不尽

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/18 01:52:24
(0.1二次方+0.2二次方+0.3二次方+0.4二次方)的二次方除以(0.1三次方+······0.4三次方简算小辈感激不尽
xRN0}Aub/,0D_`ABFD!DJ6$Wi;3͒szzzV\`}!Y3٠dcr\qh?ⷧRa}#X|.ɠ9hN]><ʍ8{%\[DR1"ZrY:HHH {qf’E+)"RDHQ)#bs`n%p4 &4)O˺zӡWMxxmک0*FX oĥ؛[_#SDhPm|pT\k[4"NoL':߈ 'âYNp貈

(0.1二次方+0.2二次方+0.3二次方+0.4二次方)的二次方除以(0.1三次方+······0.4三次方简算小辈感激不尽
(0.1二次方+0.2二次方+0.3二次方+0.4二次方)的二次方除以(0.1三次方+······0.4三次方简算
小辈感激不尽

(0.1二次方+0.2二次方+0.3二次方+0.4二次方)的二次方除以(0.1三次方+······0.4三次方简算小辈感激不尽
(0.1^2+0.2^2+0.3^2+0.4^2)^2÷(0.1^3+0.2^3+0.3^3+0.4^3)
=[(1/10)^2+(2/10)^2+(3/10)^2+(4/10)^2]^2÷[(1/10)^3+(2/10)^3+(3/10)^3+(4/10)^3]
=[(1+4+9+16)/100]^2÷[(1+8+27+64)/1000]
=(30/100)^2÷(100/1000)
=(3/10)^2÷(1/10)
=9/100÷1/10
=9/10
如果是这样的,则有:
(0.1^2+0.2^2+0.3^2+0.4^2)^2÷(0.1^3+0.2^3+0.3^3+0.4^3)^3
=[(1/10)^2+(2/10)^2+(3/10)^2+(4/10)^2]^2÷[(1/10)^3+(2/10)^3+(3/10)^3+(4/10)^3]^3
=[(1+4+9+16)/100]^2÷[(1+8+27+64)/1000]^3
=(30/100)^2÷(100/1000)^3
=(3/10)^2÷(1/10)^3
=9/100÷1/1000
=90

0.1^2=(10*-1)^2*1^2
同理0.2,0.3都一样
那么式子就可以化成
(1+4+9+16)*(10^-1)^2\(1+8+27+64)*(10^-1)^3
之后约分为3