已知命题p:函数fx=x2+ax-2在闭区间-1,1内仅有一个零点,命题q:x2+3(a+1)x+已知命题p:函数fx=x^2+ax-2在[-1,1]内仅有一个零点,命题q:x^2+3(a+1)x+2小于等于0在[二分之一,二分之三]内恒成立,若命
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![已知命题p:函数fx=x2+ax-2在闭区间-1,1内仅有一个零点,命题q:x2+3(a+1)x+已知命题p:函数fx=x^2+ax-2在[-1,1]内仅有一个零点,命题q:x^2+3(a+1)x+2小于等于0在[二分之一,二分之三]内恒成立,若命](/uploads/image/z/4331768-32-8.jpg?t=%E5%B7%B2%E7%9F%A5%E5%91%BD%E9%A2%98p%EF%BC%9A%E5%87%BD%E6%95%B0fx%3Dx2%2Bax-2%E5%9C%A8%E9%97%AD%E5%8C%BA%E9%97%B4-1%2C1%E5%86%85%E4%BB%85%E6%9C%89%E4%B8%80%E4%B8%AA%E9%9B%B6%E7%82%B9%2C%E5%91%BD%E9%A2%98q%EF%BC%9Ax2%2B3%EF%BC%88a%2B1%EF%BC%89x%2B%E5%B7%B2%E7%9F%A5%E5%91%BD%E9%A2%98p%EF%BC%9A%E5%87%BD%E6%95%B0fx%3Dx%5E2%2Bax-2%E5%9C%A8%5B-1%2C1%5D%E5%86%85%E4%BB%85%E6%9C%89%E4%B8%80%E4%B8%AA%E9%9B%B6%E7%82%B9%2C%E5%91%BD%E9%A2%98q%EF%BC%9Ax%5E2%2B3%EF%BC%88a%2B1%EF%BC%89x%2B2%E5%B0%8F%E4%BA%8E%E7%AD%89%E4%BA%8E0%E5%9C%A8%5B%E4%BA%8C%E5%88%86%E4%B9%8B%E4%B8%80%2C%E4%BA%8C%E5%88%86%E4%B9%8B%E4%B8%89%5D%E5%86%85%E6%81%92%E6%88%90%E7%AB%8B%2C%E8%8B%A5%E5%91%BD)
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