作业帮y=x^2-x+1/2x^2-2x+3 如定义域为1≤x≤5,则值域为?
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/15 19:44:42
x)3ҭ671*.kzn֓Oc%@lcӆ=Q{"}JP~
~c}#]ps4m
&
m3HFXui,ؠ{'W>Mi?trm: TBUl*1271ֳ/.H̳i"I }
y=x^2-x+1/2x^2-2x+3 如定义域为1≤x≤5,则值域为?
y=x^2-x+1/2x^2-2x+3 如定义域为1≤x≤5,则值域为?
y=x^2-x+1/2x^2-2x+3 如定义域为1≤x≤5,则值域为?
y=(x^2-x+3/2-1/2)/(2x^2-2x+3)=1/2-1/(4x^2-4x+6)=1/2-1/[4(x-1/2)^2+5]
当x=1时,取得最大值,为1/3,
当x=5时,取最小值,为21/43.
1/3,21/43
函数,y=3x/(x^2+x+1) ,x
函数y=3x/(x^2+x+1) （x
化简 3x(x^2-x-1)-(x+1)(3x^-x) X^3(x-y)+x(y-x)
3^x+2x=y,x
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
y=(2x*x-2x+3)/(x*x-x+1),求值域?
[2/3x-2/x+y(x+y/3x-x-y)]/x-y/x
化简：{2/3x-2/(x+y)[(x+y)/3x-x-y]}/(x+y)/x
计算2/3x-2/x+y(x+y/3x-x-y)/x-y/x
化简3x-2/(x+y)[(x+y)/3x-x-y]÷(x-y)/x
x(x-y)2-(y-x)3
求值域 1,y=(x+2)/(x*x+3x+6) 2,y=3x/(x*x+4)
计算：1-2x+x^2/x-x^3*xy+x^2y/x-x^2
若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7
(3x-y)^2+(3x+y)(3x-y),x=1,y=-2
二元一次方程 ：2(x+y)-(x-y)=3 (x+y)-2(x-y)=1
(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)