如图,三棱柱ABC-A1B1C1中,CA=CB,AB=A A1,∠BA A1=60°.如图,三棱柱ABC-A1B1C1中,CA=CB,AB=A A1,∠BA A1=60°.(Ⅰ)证明AB⊥A1C;(Ⅱ)若平面ABC⊥平面AA1B1B,AB=CB=2,求直线A1C与平面BB1C1C所成角的正弦值. 第二问要用传统
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![如图,三棱柱ABC-A1B1C1中,CA=CB,AB=A A1,∠BA A1=60°.如图,三棱柱ABC-A1B1C1中,CA=CB,AB=A A1,∠BA A1=60°.(Ⅰ)证明AB⊥A1C;(Ⅱ)若平面ABC⊥平面AA1B1B,AB=CB=2,求直线A1C与平面BB1C1C所成角的正弦值. 第二问要用传统](/uploads/image/z/4351666-58-6.jpg?t=%E5%A6%82%E5%9B%BE%2C%E4%B8%89%E6%A3%B1%E6%9F%B1ABC-A1B1C1%E4%B8%AD%2CCA%3DCB%2CAB%3DA+A1%2C%E2%88%A0BA+A1%3D60%C2%B0.%E5%A6%82%E5%9B%BE%2C%E4%B8%89%E6%A3%B1%E6%9F%B1ABC-A1B1C1%E4%B8%AD%2CCA%3DCB%2CAB%3DA+A1%2C%E2%88%A0BA+A1%3D60%C2%B0.%28%E2%85%A0%29%E8%AF%81%E6%98%8EAB%E2%8A%A5A1C%3B%28%E2%85%A1%29%E8%8B%A5%E5%B9%B3%E9%9D%A2ABC%E2%8A%A5%E5%B9%B3%E9%9D%A2AA1B1B%2CAB%3DCB%3D2%2C%E6%B1%82%E7%9B%B4%E7%BA%BFA1C%E4%B8%8E%E5%B9%B3%E9%9D%A2BB1C1C%E6%89%80%E6%88%90%E8%A7%92%E7%9A%84%E6%AD%A3%E5%BC%A6%E5%80%BC.++%E7%AC%AC%E4%BA%8C%E9%97%AE%E8%A6%81%E7%94%A8%E4%BC%A0%E7%BB%9F)
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