(1)lg5+1g20= (2)lg200-1g2=

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(1)lg5+1g20= (2)lg200-1g2=
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(1)lg5+1g20= (2)lg200-1g2=
(1)lg5+1g20= (2)lg200-1g2=

(1)lg5+1g20= (2)lg200-1g2=
(1)lg5+1g20=lg(5*20)=1g100=2
(2)lg200-1g2=lg(200/2)=lg100=2

(1)
lg5+1g20
=lg(5*20)
=lg100
=lg10²
=2lg10
=2
(2)
lg200-1g2
=lg(200/2)
=lg100
=lg10²
=2lg10
=2

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(1)
lg5+1g20
=lg(5*20)
=lg100
=lg10²
=2lg10
=2
(2)
lg200-1g2
=lg(200/2)
=lg100
=lg10²
=2lg10
=2

肯定对
秋风燕燕为您解答
有什么不明白可以继续问,随时在线等。
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(1)lg5+1g20
=lg(5×20)
=lg100
=lg10²
=2
(2)lg200-1g2
=lg(200÷2)
=lg100
=1g10²
=2