a,b,c为非零整数,且a²+b²+c²=1,a(1/b+1/c)+b(1/c+1/a)+c(1/a+1/b)=3,求a+b+c的值亲,初二的因式分解的题
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![a,b,c为非零整数,且a²+b²+c²=1,a(1/b+1/c)+b(1/c+1/a)+c(1/a+1/b)=3,求a+b+c的值亲,初二的因式分解的题](/uploads/image/z/4492079-71-9.jpg?t=a%2Cb%2Cc%E4%B8%BA%E9%9D%9E%E9%9B%B6%E6%95%B4%E6%95%B0%2C%E4%B8%94a%26%23178%3B%2Bb%26%23178%3B%2Bc%26%23178%3B%3D1%2Ca%281%2Fb%2B1%2Fc%29%2Bb%281%2Fc%2B1%2Fa%29%2Bc%281%2Fa%2B1%2Fb%29%3D3%2C%E6%B1%82a%2Bb%2Bc%E7%9A%84%E5%80%BC%E4%BA%B2%2C%E5%88%9D%E4%BA%8C%E7%9A%84%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E7%9A%84%E9%A2%98)
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a,b,c为非零整数,且a²+b²+c²=1,a(1/b+1/c)+b(1/c+1/a)+c(1/a+1/b)=3,求a+b+c的值亲,初二的因式分解的题
a,b,c为非零整数,且a²+b²+c²=1,a(1/b+1/c)+b(1/c+1/a)+c(1/a+1/b)=3,求a+b+c的值
亲,初二的因式分解的题
a,b,c为非零整数,且a²+b²+c²=1,a(1/b+1/c)+b(1/c+1/a)+c(1/a+1/b)=3,求a+b+c的值亲,初二的因式分解的题
a,b,c为非零整数,这句话已经让这道题目无解了.
本来还可以通过1的代换将1换成a²+b²+c²来做,求出a+b+c的,但是因为a(1/b+1/c)+b(1/c+1/a)+c(1/a+1/b)=3而不是-3,本来a+b+c=正负1或0,现在就没法做了