已知2x+y+3z=23(1),x+4y+5z=36(2),求x+2y+3z的值
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已知2x+y+3z=23(1),x+4y+5z=36(2),求x+2y+3z的值
已知2x+y+3z=23(1),x+4y+5z=36(2),求x+2y+3z的值
已知2x+y+3z=23(1),x+4y+5z=36(2),求x+2y+3z的值
2×(2)-(1)得:y+z=7;4×(1)-(2)得:x+z=8;则:x+2y+3z=(x+z)+2(y+z)=22.
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