把0.02mol/LHAc溶液和0.01mol/LNaOH溶液以等体积混和,则混合液中微粒浓度关系正确的为(A) C(AC-)>C(Na+) (B) C(HAc)>C(Ac-)(C) 2C(H+)=C(Ac-)-C(HAc) (D) C(HAc)+C(Ac-)=0.01mol/L 答案为AD,麻烦详细分析一下每个选项,谢谢
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/19 14:32:47
![把0.02mol/LHAc溶液和0.01mol/LNaOH溶液以等体积混和,则混合液中微粒浓度关系正确的为(A) C(AC-)>C(Na+) (B) C(HAc)>C(Ac-)(C) 2C(H+)=C(Ac-)-C(HAc) (D) C(HAc)+C(Ac-)=0.01mol/L 答案为AD,麻烦详细分析一下每个选项,谢谢](/uploads/image/z/4757854-22-4.jpg?t=%E6%8A%8A0.02mol%2FLHAc%E6%BA%B6%E6%B6%B2%E5%92%8C0.01mol%2FLNaOH%E6%BA%B6%E6%B6%B2%E4%BB%A5%E7%AD%89%E4%BD%93%E7%A7%AF%E6%B7%B7%E5%92%8C%2C%E5%88%99%E6%B7%B7%E5%90%88%E6%B6%B2%E4%B8%AD%E5%BE%AE%E7%B2%92%E6%B5%93%E5%BA%A6%E5%85%B3%E7%B3%BB%E6%AD%A3%E7%A1%AE%E7%9A%84%E4%B8%BA%28A%29+C%28AC-%29%3EC%28Na%2B%29+%28B%29+C%28HAc%29%3EC%28Ac-%29%28C%29+2C%28H%2B%29%3DC%28Ac-%29-C%28HAc%29+%28D%29+C%28HAc%29%2BC%28Ac-%29%3D0.01mol%2FL+%E7%AD%94%E6%A1%88%E4%B8%BAAD%2C%E9%BA%BB%E7%83%A6%E8%AF%A6%E7%BB%86%E5%88%86%E6%9E%90%E4%B8%80%E4%B8%8B%E6%AF%8F%E4%B8%AA%E9%80%89%E9%A1%B9%2C%E8%B0%A2%E8%B0%A2)
xSnPwgSҬ"cYT(>PFb,TTMäIb%ޗW}IvUR7X\Μ3gfԋxF9_>O2R}Q_PD:b$ei8^ G.nЛxgt4G(DU4QRQ+՜$QkyI$aŁ<bね
s ,'QL.]&m(|G
$2Oy/gz0{ NQ\74EF3Xs2Y8rsBUj:3x/Fdj䃙Dmig2..-z'