化学方程式的配平Cr03+C2H5OH+H2SO4-Cr(SO4)3+CH3CHO+H2OCr03+C2H5OH+H2SO4-Cr2(SO4)3+CH3CHO+H2O 检测酒后驾车的那个东东~~~这个反应的方程式咋配平的,就是方法,我咋找不到~~~~高人指点下,方法详细下,~谢谢~~~喽
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/12 12:36:33
![化学方程式的配平Cr03+C2H5OH+H2SO4-Cr(SO4)3+CH3CHO+H2OCr03+C2H5OH+H2SO4-Cr2(SO4)3+CH3CHO+H2O 检测酒后驾车的那个东东~~~这个反应的方程式咋配平的,就是方法,我咋找不到~~~~高人指点下,方法详细下,~谢谢~~~喽](/uploads/image/z/4784664-48-4.jpg?t=%E5%8C%96%E5%AD%A6%E6%96%B9%E7%A8%8B%E5%BC%8F%E7%9A%84%E9%85%8D%E5%B9%B3Cr03%2BC2H5OH%2BH2SO4-Cr%28SO4%293%2BCH3CHO%2BH2OCr03%2BC2H5OH%2BH2SO4-Cr2%28SO4%293%2BCH3CHO%2BH2O+%E6%A3%80%E6%B5%8B%E9%85%92%E5%90%8E%E9%A9%BE%E8%BD%A6%E7%9A%84%E9%82%A3%E4%B8%AA%E4%B8%9C%E4%B8%9C%7E%7E%7E%E8%BF%99%E4%B8%AA%E5%8F%8D%E5%BA%94%E7%9A%84%E6%96%B9%E7%A8%8B%E5%BC%8F%E5%92%8B%E9%85%8D%E5%B9%B3%E7%9A%84%2C%E5%B0%B1%E6%98%AF%E6%96%B9%E6%B3%95%2C%E6%88%91%E5%92%8B%E6%89%BE%E4%B8%8D%E5%88%B0%7E%7E%7E%7E%E9%AB%98%E4%BA%BA%E6%8C%87%E7%82%B9%E4%B8%8B%2C%E6%96%B9%E6%B3%95%E8%AF%A6%E7%BB%86%E4%B8%8B%2C%7E%E8%B0%A2%E8%B0%A2%7E%7E%7E%E5%96%BD)
化学方程式的配平Cr03+C2H5OH+H2SO4-Cr(SO4)3+CH3CHO+H2OCr03+C2H5OH+H2SO4-Cr2(SO4)3+CH3CHO+H2O 检测酒后驾车的那个东东~~~这个反应的方程式咋配平的,就是方法,我咋找不到~~~~高人指点下,方法详细下,~谢谢~~~喽
化学方程式的配平Cr03+C2H5OH+H2SO4-Cr(SO4)3+CH3CHO+H2O
Cr03+C2H5OH+H2SO4-Cr2(SO4)3+CH3CHO+H2O 检测酒后驾车的那个东东~~~这个反应的方程式咋配平的,就是方法,我咋找不到~~~~高人指点下,方法详细下,~谢谢~~~喽~~
化学方程式的配平Cr03+C2H5OH+H2SO4-Cr(SO4)3+CH3CHO+H2OCr03+C2H5OH+H2SO4-Cr2(SO4)3+CH3CHO+H2O 检测酒后驾车的那个东东~~~这个反应的方程式咋配平的,就是方法,我咋找不到~~~~高人指点下,方法详细下,~谢谢~~~喽
(1)一般的方程式用电子得失配平,这道题可以用待定系数法(比较数学化),设Cr2(SO4)3,为X,所以Cr03为2X,H2SO4为3X,在设CH3CHO为Y,所以C2H5OH为Y,设H2O为Z,所以H守恒,5Y+6X=4Y+2Z,O守恒,6X+6Y+12X=12X+4Y+Z,可得X:Y:Z. (2)电子得失,因为Cr03中Cr为+6价,Cr2(SO4)3,中Cr为+3价,对于1molCr2(SO4)3,Cr降低得到2*(6-3)=6mol电子,C2H5OH中两个碳化合价为-3和-1,CH3CHO中两个碳化合价为-3和+1,所以对于1molCH3CHO,C失去2mol电子,所以CH3CHO:Cr2(SO4)3=6:2=3:1,2,再由元素守恒可配平为2 3 3 1 3 6.
记得采纳啊