在梯形ABCD中,AB//CD,AB⊥BC,AB+DC=BC,点P是AD的中点在梯形ABCD中,AB//CD,AB⊥BC,AB+DC=BC,点P是AD的中点(1)求证:PB⊥PC(2)若AB=2,CD=4,M为BC边上点,且AM⊥MD,求BM的长(3)设AM与BP交于点E,DM与CP交于点F,在(2)的条
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![在梯形ABCD中,AB//CD,AB⊥BC,AB+DC=BC,点P是AD的中点在梯形ABCD中,AB//CD,AB⊥BC,AB+DC=BC,点P是AD的中点(1)求证:PB⊥PC(2)若AB=2,CD=4,M为BC边上点,且AM⊥MD,求BM的长(3)设AM与BP交于点E,DM与CP交于点F,在(2)的条](/uploads/image/z/4971431-47-1.jpg?t=%E5%9C%A8%E6%A2%AF%E5%BD%A2ABCD%E4%B8%AD%2CAB%2F%2FCD%2CAB%E2%8A%A5BC%2CAB%2BDC%3DBC%2C%E7%82%B9P%E6%98%AFAD%E7%9A%84%E4%B8%AD%E7%82%B9%E5%9C%A8%E6%A2%AF%E5%BD%A2ABCD%E4%B8%AD%2CAB%2F%2FCD%2CAB%E2%8A%A5BC%2CAB%2BDC%3DBC%2C%E7%82%B9P%E6%98%AFAD%E7%9A%84%E4%B8%AD%E7%82%B9%281%29%E6%B1%82%E8%AF%81%EF%BC%9APB%E2%8A%A5PC%282%29%E8%8B%A5AB%3D2%2CCD%3D4%2CM%E4%B8%BABC%E8%BE%B9%E4%B8%8A%E7%82%B9%2C%E4%B8%94AM%E2%8A%A5MD%2C%E6%B1%82BM%E7%9A%84%E9%95%BF%283%29%E8%AE%BEAM%E4%B8%8EBP%E4%BA%A4%E4%BA%8E%E7%82%B9E%2CDM%E4%B8%8ECP%E4%BA%A4%E4%BA%8E%E7%82%B9F%2C%E5%9C%A8%EF%BC%882%EF%BC%89%E7%9A%84%E6%9D%A1)
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