在△ABC中,∠BAC的平分线AD交BC于D,且AB=AD,作CM⊥AD交AD的延长线于M,证明:AM=1/2(AB+AC)
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![在△ABC中,∠BAC的平分线AD交BC于D,且AB=AD,作CM⊥AD交AD的延长线于M,证明:AM=1/2(AB+AC)](/uploads/image/z/4978221-69-1.jpg?t=%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0BAC%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BFAD%E4%BA%A4BC%E4%BA%8ED%2C%E4%B8%94AB%3DAD%2C%E4%BD%9CCM%E2%8A%A5AD%E4%BA%A4AD%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%8EM%2C%E8%AF%81%E6%98%8E%EF%BC%9AAM%3D1%2F2%EF%BC%88AB%2BAC%EF%BC%89)
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