3^13=,3^2=9,3^3=27,3^4=81,.3^2010的末位数字是
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/06 04:24:06
x)33413ƶF@PG(h`h|V˳9}6uӵӟXoTO>;lTU0VE
Py#%yK1PsC,
LA&sP>W03S3.y˛|RcPYlN`=ݰ|Ov/5ֱ11|c}g6Ĕ
?qS#FP-
0p._@Q
ѱ]
3^13=,3^2=9,3^3=27,3^4=81,.3^2010的末位数字是
3^13=,3^2=9,3^3=27,3^4=81,.3^2010的末位数字是
3^13=,3^2=9,3^3=27,3^4=81,.3^2010的末位数字是
3^1 = 3 ----------------- 3
3^2 = 9 ----------------- 9
3^3 = 27 ----------------- 7
3^4 = 81 ----------------- 1
3^5 = 243 ----------------- 3
3^6 = 729 ----------------- 9
3^7 = 2187 ----------------- 7
3^8 = 6561 ----------------- 1
……
观察知,3的次方末尾数字以3,9,7,1为循环;
∵ 2010÷4 = 502……2
∴ 3^2010的末尾数字为 9
3^13=,3^2=9,3^3=27,3^4=81,.3^2010的末位数字是
9x+3x-27+13=67解方程
()/9 =2:3=():27=8:()
解方程组:3(x-3)+10(2/3+y)=13,22(x-3)+5(2/3+y)=27
27^2*9^4=3^k,k=
数学题13-9=3()=()
3*9^m*27^m=3^21.m=?
数学题:3:()=27
3^1=3,3^2=9,3^3=27,3^4=81,.那么3^2008的末位数字是?
3^1=3,3^2=9,3^3=27,3^4=81,.那么3^2008的末位数字是?
3×9^n×27^n-1=3 x 3^2n x 3^(3n-3) 怎么转换的
2/3=6/( )=( )/15=24/( ) 18%=9/ ( )=36/( )=27/( )
简便运算;27×(-2/3)+(-15)×2/3-9×2/3=
2M^3-9M^2+27=0
已知3^1=3,3^2=9,3^3=27,3^4=81,3^5=243,3^6=729,3^7=2187,… 推测3^20的个位数字是多少?
已知3^1=3,3^2=9,3^3=27,3^4=81,3^5=243,3^6=729,3^7=2187...推测3^20的个位数是多少有用一点采纳
已知3^ 1=3,3^ 2=9,3^ 3=27,3^4 =81,3^5=243,3^ 6=729,...3^ 8=6561.猜想3^ 2012的末尾数字是( )
x平方/27+16/36=1.此题我分别求出了正负根号3 与正负根号15 为什么呢?x平方/27+4/9=1x/3倍根号3+2/3=1x/3倍根号3=3/13x= 3倍根号3x=根号3