如图,把A、B小球由图中上位置同时由静止释放(绳开始时拉直),下列正确的是( )A.绳OA对A球做正功B.绳AB对B球不做功C.绳AB对A球做负功D.绳AB对B球做正功

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如图,把A、B小球由图中上位置同时由静止释放(绳开始时拉直),下列正确的是( )A.绳OA对A球做正功B.绳AB对B球不做功C.绳AB对A球做负功D.绳AB对B球做正功
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如图,把A、B小球由图中上位置同时由静止释放(绳开始时拉直),下列正确的是( )A.绳OA对A球做正功B.绳AB对B球不做功C.绳AB对A球做负功D.绳AB对B球做正功
如图,把A、B小球由图中上位置同时由静止释放(绳开始时拉直)
,下列正确的是( )
A.绳OA对A球做正功
B.绳AB对B球不做功
C.绳AB对A球做负功
D.绳AB对B球做正功

如图,把A、B小球由图中上位置同时由静止释放(绳开始时拉直),下列正确的是( )A.绳OA对A球做正功B.绳AB对B球不做功C.绳AB对A球做负功D.绳AB对B球做正功
答案是D,因为球A,B角速度相等,而半径0B大于OA,故B球速度大于A球,即B球动能大于A球.但是A,B下降高度时刻相等,所以B多出的动能由绳AB做正功提供,选D.
码字挺累的,

∵力的方向斜向上
∴那个力的分力与位移方向相反
∴绳OA对A做负功
但∵A和B同时被释放
∴都做自由落体运动
∴状态与原来的状态一样
∴绳AB不会对B做功

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B
力与速度垂直,所以始终不做功。

A,B两球在下降过程中重力势能的减少量相同,可以考虑为重力势能转化为动能,在某一点的动能之和是一定的,如果A,B同高则动能相同互不影响,图中明显B的动能大于A的动能,有A通过绳AB对B做功

如图,把A、B小球由图中上位置同时由静止释放(绳开始时拉直) ,下列如图,把A、B小球由图中上位置同时由静止释放(绳开始时拉直),下列正确的是( )A.绳OA对A球做正功B.绳AB对B球不做功C.绳A 如图,把A、B小球由图中上位置同时由静止释放(绳开始时拉直),下列正确的是( )A.绳OA对A球做正功B.绳AB对B球不做功C.绳AB对A球做负功D.绳AB对B球做正功 把A,B小球由图中位置同时由静止释放,(绳开始时拉直)把A,B小球由图中位置同时由静止释放,(绳开始时拉直)则在两小球向下运动的过程中( )A.绳OA对A球做正功B.绳AB对B球做负功C.绳AB 如图2所示,把AB小球由图中位置同时由静止释放,(绳开始时拉直)则在两小球 ( )A.绳OA对A球做正功 B.绳AB对B球不做功C.绳AB对B球做负功 D.绳AB对B球做正功因为没有图,就是一根绳子的一端固 如图,把系在轻绳上的AB两小球由图示位置同时由静止释放(绳开始时拉直),两小球向左下摆动,下列正确的是( )A.绳OA对A球做正功B.绳AB对B球不做功C.绳AB对A球做负功D.绳AB对B球做正功 圆周运动做功问题!如图7-5所示,把系在轻绳上的A、B两球由图示位置同时由静止释放(绳开始时拉直),则在两小球向左下摆动时,下列说法正确的是:( )A.绳OA对A球做正功 B.绳AB对B球不做功C.绳 把AB小球由图中位置同时由静止释放,(绳开始时拉直)则在两小球这是原题!我的问题是:所以AB绳对A球做负功,对B球做正功他为什么可以判断出做负功?不是不是!1.2楼的。我的意思是我知道 把AB小球由图中位置同时由静止释放,(绳开始时拉直)则在两小球:为什么A的角速度要比B 他们不是一起下落同心圆吗?那假设不是同心圆,那么又怎么能推出角速度的关系呢?我不是很清楚原 如图1.2-9所示,把一质量为m的带点量为-q的小球,用长为L的绝缘细线悬挂在水平方向的匀强电场中,开始时将小球拉至水平位置A点,然后由静止开始释放,小球运动到B点时速度恰好为零,求电场强 如图,长为L的细绳,一端系着一小球,一段悬于o点,将小球由图示位置由静止释放图:为啥是d? 把系在轻绳上的AB两小球由图示位置同时由静止释放(绳开始时拉直),两小球向左下摆动下列正确的是( )A.绳OA对A球做正功B.绳AB对B球不做功C.绳AB对A球做负功D.绳AB对B球做正功我想问如何分析出 图所示,让小球从位置A由静止开始下摆,正好摆到最低点B时摆线被拉断,设摆线长l=1.6m,悬点到地面的高度为h如图所示,让小球从位置A由静止开始向下摆,正好摆到最低点B时摆线被拉断,设摆线长l 弹簧振子在水平面作间谐振动.O为平衡位置,A、B为最大位移.从A开始振动,第二次经过O时用时t秒.在O点上方P处有一个小球.振子由A点,小球由P点同时由静止释放,恰好在O点处相碰.求小球所在高 一个弹簧振子在水平面内做简谐振动,O为平衡位置,A、B为最大位移处,振子从A点开始振动,测得第二次经过平衡位置O时所用时间t s,在O点上方P处有一个小球,现使振子由A点,小球由P点同时由静止 如图7-17所示,一质量为m的小球固定于轻质弹簧的一端,弹簧的另一端固定在O处,在图示位置恰好无形变.现由静止放开小球,它运动到O点正下方B处的速度为v,A、B间的高度差为h,则(    ) 高中物理有技术含量的高考题在一种新的“子母球”表演中,让同一竖直线上的小球A和小球B,从距水平地面高度为ph(p>1)和h的地方同时由静止释放,如题9图所示.球A的质量为m,球B的质量为3m. 1.如图8—51所示,小球自a点由静止自由下落,到b点时与弹簧接触,到c点时弹簧被压缩至最短,若不计弹簧的质量和空气阻力,小球由a→b→c的运动过程中 A.小球的动能逐渐减小 B.小球 质量为m的小球用长0.8m的轻线系住悬挂起来.题目在下面.把小球拉离水平位子.试选线绷直并于竖直方向成60°,如图小球由静止释放后不计空气阻力机械能守恒小球运动至平衡位置时的速度为.A8