试确定实数a的取值范围,使不等式组 恰有两个整数解.由 x/2+(x+1)/3>0,两边同乘以6得3x+2(x+1)>0,解得x>- 2/5,由x+(5a+4)/3>4/3(x+1)+a,两边同乘以3得3x+5a+4>4(x+1)+3a,解得x<2a,
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![试确定实数a的取值范围,使不等式组 恰有两个整数解.由 x/2+(x+1)/3>0,两边同乘以6得3x+2(x+1)>0,解得x>- 2/5,由x+(5a+4)/3>4/3(x+1)+a,两边同乘以3得3x+5a+4>4(x+1)+3a,解得x<2a,](/uploads/image/z/5075796-12-6.jpg?t=%E8%AF%95%E7%A1%AE%E5%AE%9A%E5%AE%9E%E6%95%B0a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%2C%E4%BD%BF%E4%B8%8D%E7%AD%89%E5%BC%8F%E7%BB%84+%E6%81%B0%E6%9C%89%E4%B8%A4%E4%B8%AA%E6%95%B4%E6%95%B0%E8%A7%A3%EF%BC%8E%E7%94%B1+x%2F2%2B%28x%2B1%29%2F3%EF%BC%9E0%EF%BC%8C%E4%B8%A4%E8%BE%B9%E5%90%8C%E4%B9%98%E4%BB%A56%E5%BE%973x%2B2%EF%BC%88x%2B1%EF%BC%89%EF%BC%9E0%EF%BC%8C%E8%A7%A3%E5%BE%97x%EF%BC%9E-+2%2F5%EF%BC%8C%E7%94%B1x%2B%EF%BC%885a%2B4%EF%BC%89%2F3%EF%BC%9E4%2F3%EF%BC%88x%2B1%EF%BC%89%2Ba%EF%BC%8C%E4%B8%A4%E8%BE%B9%E5%90%8C%E4%B9%98%E4%BB%A53%E5%BE%973x%2B5a%2B4%EF%BC%9E4%EF%BC%88x%2B1%EF%BC%89%2B3a%EF%BC%8C%E8%A7%A3%E5%BE%97x%EF%BC%9C2a%EF%BC%8C)
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