若不等式4x-3a≤5a的正整数解是1和2,则a的取值范围是我就是搞不懂用数轴怎么的出结果的4x-3a≤5a4x≤8ax≤2a然后根据不等式4x-3a≤5a的正整数解是1和2怎么就可以得出a的取值范围是1≤a≤1.5的呢
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![若不等式4x-3a≤5a的正整数解是1和2,则a的取值范围是我就是搞不懂用数轴怎么的出结果的4x-3a≤5a4x≤8ax≤2a然后根据不等式4x-3a≤5a的正整数解是1和2怎么就可以得出a的取值范围是1≤a≤1.5的呢](/uploads/image/z/5122155-3-5.jpg?t=%E8%8B%A5%E4%B8%8D%E7%AD%89%E5%BC%8F4x-3a%E2%89%A45a%E7%9A%84%E6%AD%A3%E6%95%B4%E6%95%B0%E8%A7%A3%E6%98%AF1%E5%92%8C2%2C%E5%88%99a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%E6%98%AF%E6%88%91%E5%B0%B1%E6%98%AF%E6%90%9E%E4%B8%8D%E6%87%82%E7%94%A8%E6%95%B0%E8%BD%B4%E6%80%8E%E4%B9%88%E7%9A%84%E5%87%BA%E7%BB%93%E6%9E%9C%E7%9A%844x-3a%E2%89%A45a4x%E2%89%A48ax%E2%89%A42a%E7%84%B6%E5%90%8E%E6%A0%B9%E6%8D%AE%E4%B8%8D%E7%AD%89%E5%BC%8F4x-3a%E2%89%A45a%E7%9A%84%E6%AD%A3%E6%95%B4%E6%95%B0%E8%A7%A3%E6%98%AF1%E5%92%8C2%E6%80%8E%E4%B9%88%E5%B0%B1%E5%8F%AF%E4%BB%A5%E5%BE%97%E5%87%BAa%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%E6%98%AF1%E2%89%A4a%E2%89%A41.5%E7%9A%84%E5%91%A2)
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