已知全集U={-2,1,a+3,a^2-a-2},(a∈R)A∈U,CuA={4},求集合A已知全集U={-2,1,a+3,a^2-a-2},(a∈R)A∈U,CuA={4},求集合A

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已知全集U={-2,1,a+3,a^2-a-2},(a∈R)A∈U,CuA={4},求集合A已知全集U={-2,1,a+3,a^2-a-2},(a∈R)A∈U,CuA={4},求集合A
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已知全集U={-2,1,a+3,a^2-a-2},(a∈R)A∈U,CuA={4},求集合A已知全集U={-2,1,a+3,a^2-a-2},(a∈R)A∈U,CuA={4},求集合A
已知全集U={-2,1,a+3,a^2-a-2},(a∈R)A∈U,CuA={4},求集合A
已知全集U={-2,1,a+3,a^2-a-2},(a∈R)A∈U,CuA={4},求集合A

已知全集U={-2,1,a+3,a^2-a-2},(a∈R)A∈U,CuA={4},求集合A已知全集U={-2,1,a+3,a^2-a-2},(a∈R)A∈U,CuA={4},求集合A
设a+3=4,则a^2-a-2=-2
所以不符合集合的唯一性
设a^2-a-2=4 解得a1=3 a2=-2
当a=3,a+3=6
所以A={-2,1,6}
当a=-2,a+3=1
不符
所以A={-2,1,6}

设a+3=4,则a^2-a-2=-2
所以不符合集合的唯一性
设a^2-a-2=4 解得a1=3 a2=-2
当a=3,a+3=6
所以A={-2,1,6}
当a=-2,a+3=1
不符
所以A={-2,1,6}
求采纳~