(2sin²α+2sinα*cosα)/(1+tanα)=2sinacosa 这是怎么算的?
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![(2sin²α+2sinα*cosα)/(1+tanα)=2sinacosa 这是怎么算的?](/uploads/image/z/5188959-63-9.jpg?t=%EF%BC%882sin%26%23178%3B%CE%B1%2B2sin%CE%B1%2Acos%CE%B1%29%2F%EF%BC%881%2Btan%CE%B1%EF%BC%89%3D2sinacosa+%E8%BF%99%E6%98%AF%E6%80%8E%E4%B9%88%E7%AE%97%E7%9A%84%3F)
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(2sin²α+2sinα*cosα)/(1+tanα)=2sinacosa 这是怎么算的?
(2sin²α+2sinα*cosα)/(1+tanα)=2sinacosa 这是怎么算的?
(2sin²α+2sinα*cosα)/(1+tanα)=2sinacosa 这是怎么算的?
(2sin²α+2sinα*cosα)/(1+tanα)
=2sinα(sinα+cosα)/(1+sinα/cosα)
=2sinα(sinα+cosα)/[(sinα+cosα)/cosα]
=2sinαcosα
(2sin²α+2sinα*cosα)/(1+tanα)
=2sinα(sinα+cosα)/ [ (sinα+cosα)/cosα]
=2sinαcosα