x2+1/x2-x1-1/x1怎么到(x2-x1)(1-1/x1x2)
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/29 06:46:14
![x2+1/x2-x1-1/x1怎么到(x2-x1)(1-1/x1x2)](/uploads/image/z/5197182-6-2.jpg?t=x2%2B1%2Fx2-x1-1%2Fx1%E6%80%8E%E4%B9%88%E5%88%B0%EF%BC%88x2-x1%29%281-1%2Fx1x2%29)
x)06ԯ0ҭ0҆xڱDH&H$v6 Հ( ġPؠX9d$ف R]
x2+1/x2-x1-1/x1怎么到(x2-x1)(1-1/x1x2)
x2+1/x2-x1-1/x1怎么到(x2-x1)(1-1/x1x2)
x2+1/x2-x1-1/x1怎么到(x2-x1)(1-1/x1x2)
x2+1/x2-x1-1/x1
=(x2-x1)-(1/x1-1/x2)
=(x2-x1)-[(x2-x1)/x1x2]
=(x2-x1)(1-1/x1x2)
x2+1/x2-x1-1/x1怎么到(x2-x1)(1-1/x1x2)
疑难数学问题火急求助x1^3-3x1^2+2x1+x2→x1(x1^2-2x1+2-x1)+x2→x1(3-x1)+x2 (怎么算出3-X1的)→3x1-x1^2+x2=2x1-x^2+x1+x2=-(x^2-2x1)+x1+x2=-1+2=1
(x2-x1)+ (x1-x2/x1x2) 怎样变形到(x2-x1)(1-1/x1x2)(x2-x1)+ x1-x2/x1x2 怎样变形到 (x2-x1)(1-1/x1x2)?
(x1-1分之x1)-(x2-1分之x2)怎么变形
X2/X1(X1+X2)+X3/(X1+X2)(X1+X2+X3)+.Xn/(x1+x2+...Xn-1)(X1+X2...+Xn)
X1+1/X1-X2-1/X2 因式分解
x2 -x1 + (x1-x2)/x1x2 怎么化成(x2 -x1)*(1 - 1/x1x2)
x2-x1+{-(x2-x1)/x2x1}怎么分解成(x2-x1)(1-1/x2x1)
怎么倒的(X1-X2)+3/X1-3/X2=(X1-x2)[1+3/X1X2]
证明:函数f(x)=X^2+1负无穷到0之间是减函数设X1,X2∈(-∞,0),且X1>X2则f(X1)-f(X2)=X1²-X2²=(X1+X2)*(X1-X2)因为X1+X20所以f(X1)-f(X2)懂了因为X1,X2∈(-∞,0),
讨论函数f(x)=x/x2+1的单调性和奇偶性.解到[X1X2(X2-X1)+(X1-X2)]不知道怎么判断了
数学化简看不懂,第2步怎么来的?x2+1/x2-x1-1/x1=(x2-x1)-(x2-x1)/(x1x2)=(x2-x1)(1-1/x1x2)
已知x1,x2是方程2x^2+3x-4=0的两个根试求:x1+x2,x1.x2,1/x1+1/x2,x1^2+x2^2,(x1+1)(x2+1),x1-x2绝对值,的值.
√x2/x1 + √x1/x2 =怎么推导 用韦达定理推设一元二次方程2x²+7x+1=0两个根x1 x2,不解方程求值x2/x1+x1/x2|x1-x2|√(x2/x1) + √(x1/x2)
证明函数f(x)=-x²+2x在(负无穷,-1】上是增函数中的一个问题!任取x1,x2∈(-∞,-1],且x1>x2∴f(x1)-f(x2)=-x1²+2x1-(-x2²+2x2)=x2²-x1²+2x1-2x2=(x2+x1)(x2-x1)+2(x1-x2)=(x2-x1)(x2+x1-2)∵x1>x2,x1,x2∈(-∞,-1]
(5.2x1.1x2十3x1.1x2-1)x1怎么算
设方程x2+x-1=0的两个根为x1,x2,求:【1】 (x1+1)(x2+1) 【2】x1/x2+x2/x1
已知函数f(x)=tanx,x属于0到90度,若x1,x2都属于0到90度,且x1≠x2,求证:1/2{f(x1)+f(x2)}>f{(x1+x2)/2}