已知X∶Y∶Z=2∶3∶4,且X+Z+减Y=36,求X+Y+Z的值

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已知X∶Y∶Z=2∶3∶4,且X+Z+减Y=36,求X+Y+Z的值
已知X∶Y∶Z=2∶3∶4,且X+Z+减Y=36,求X+Y+Z的值

已知X∶Y∶Z=2∶3∶4,且X+Z+减Y=36,求X+Y+Z的值
设x=2a,y=3a,z=4a,则
x+z-y=2a+4a-3a= 3a= 36
所以a=12
所以 x+y+z=2a+3a+4a=9a=9*12=108

设x=2a,y=3a,z=4a有x+y-z=2a+3a-4a=a=3,则x+y+z=2a+3a+4a=9a=9*3=27

y=1.5x z=2x
x+z-y=x+2x-1.5x=1.5x=36 x=24
x+y+z=x+1.5x+2x=4.5x=108

等于108.
解答:设X为2N,Y为3N,Z为4N.ZE.则X+Z-Y=2N+4N-3N=3N=36,所以N=12.则X=24,Y=36,Z=48,所以X+Y+Z=108.
你觉得是对的吗?

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