∫dx/(x+1)^4/3*(x-1)^2/3=∫[(x-1)/(x+1)]^1/3*dx/(x^2-1),这一步怎么解出来的?还有∫xdx/[4-x^2+(4-x^2)^1/2]=∫[1/(4-x^2)^1/2+1]*xdx/(4-x^2)^1/2,这一步怎么解出来的,
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![∫dx/(x+1)^4/3*(x-1)^2/3=∫[(x-1)/(x+1)]^1/3*dx/(x^2-1),这一步怎么解出来的?还有∫xdx/[4-x^2+(4-x^2)^1/2]=∫[1/(4-x^2)^1/2+1]*xdx/(4-x^2)^1/2,这一步怎么解出来的,](/uploads/image/z/5212506-66-6.jpg?t=%E2%88%ABdx%2F%28x%2B1%29%5E4%2F3%2A%28x-1%29%5E2%2F3%3D%E2%88%AB%5B%28x-1%29%2F%EF%BC%88x%2B1%29%5D%5E1%2F3%2Adx%2F%28x%5E2-1%29%2C%E8%BF%99%E4%B8%80%E6%AD%A5%E6%80%8E%E4%B9%88%E8%A7%A3%E5%87%BA%E6%9D%A5%E7%9A%84%3F%E8%BF%98%E6%9C%89%E2%88%ABxdx%2F%5B4-x%5E2%2B%284-x%5E2%29%5E1%2F2%5D%3D%E2%88%AB%5B1%2F%284-x%5E2%29%5E1%2F2%2B1%5D%2Axdx%2F%284-x%5E2%29%5E1%2F2%2C%E8%BF%99%E4%B8%80%E6%AD%A5%E6%80%8E%E4%B9%88%E8%A7%A3%E5%87%BA%E6%9D%A5%E7%9A%84%2C)
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