在△ABC中,向量m=(cosC/2,sinC/2),向量n=(cosC/2,-sinC/2),且向量m,向量n的夹角为π/3.求角C的值 .已知c=7/2,△ABC面积S=二分之三倍根号三,求a,b的值
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![在△ABC中,向量m=(cosC/2,sinC/2),向量n=(cosC/2,-sinC/2),且向量m,向量n的夹角为π/3.求角C的值 .已知c=7/2,△ABC面积S=二分之三倍根号三,求a,b的值](/uploads/image/z/5212846-46-6.jpg?t=%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2C%E5%90%91%E9%87%8Fm%3D%EF%BC%88cosC%2F2%2CsinC%2F2%EF%BC%89%2C%E5%90%91%E9%87%8Fn%3D%EF%BC%88cosC%2F2%2C-sinC%2F2%EF%BC%89%2C%E4%B8%94%E5%90%91%E9%87%8Fm%2C%E5%90%91%E9%87%8Fn%E7%9A%84%E5%A4%B9%E8%A7%92%E4%B8%BA%CF%80%2F3.%E6%B1%82%E8%A7%92C%E7%9A%84%E5%80%BC+.%E5%B7%B2%E7%9F%A5c%3D7%2F2%2C%E2%96%B3ABC%E9%9D%A2%E7%A7%AFS%3D%E4%BA%8C%E5%88%86%E4%B9%8B%E4%B8%89%E5%80%8D%E6%A0%B9%E5%8F%B7%E4%B8%89%2C%E6%B1%82a%2Cb%E7%9A%84%E5%80%BC)
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