分解因式(x+y-2xy)(x+y-2)(xy-1)平方=

来源:学生作业帮助网 编辑:作业帮 时间:2024/09/30 09:03:04
分解因式(x+y-2xy)(x+y-2)(xy-1)平方=
x){b⧳<~OGvQE=0Ykd=ݹٴ6IE(:k/&TT&E4u4AFfX61H(1 M@$mC 96Dy"Ђ$M , R 1?

分解因式(x+y-2xy)(x+y-2)(xy-1)平方=
分解因式
(x+y-2xy)(x+y-2)(xy-1)平方=

分解因式(x+y-2xy)(x+y-2)(xy-1)平方=
设x+y=a,xy=b
(a-2b)(a-2)+(b-1)^2
=a^2-2ab-2a+4b+b^2-2b+1
=a^2-2ab-2a+b^2+2b+1
=a^2-2ab+b^2-2a+2b+1
=(a-b)^2-2(a-b)+1
=(a-b-1)^2