如图,在菱形ABCD中,角DAB=60°,E是AB的中点,MA⊥平面ABCD,且在矩形ADMN中,AD=2,AM=(3根号7)/2(1)求证AC⊥BN (2) 求证AN∥平面MEC
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![如图,在菱形ABCD中,角DAB=60°,E是AB的中点,MA⊥平面ABCD,且在矩形ADMN中,AD=2,AM=(3根号7)/2(1)求证AC⊥BN (2) 求证AN∥平面MEC](/uploads/image/z/5225837-5-7.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E8%8F%B1%E5%BD%A2ABCD%E4%B8%AD%2C%E8%A7%92DAB%3D60%C2%B0%2CE%E6%98%AFAB%E7%9A%84%E4%B8%AD%E7%82%B9%2CMA%E2%8A%A5%E5%B9%B3%E9%9D%A2ABCD%2C%E4%B8%94%E5%9C%A8%E7%9F%A9%E5%BD%A2ADMN%E4%B8%AD%2CAD%3D2%2CAM%3D%EF%BC%883%E6%A0%B9%E5%8F%B77%EF%BC%89%2F2%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81AC%E2%8A%A5BN++%282%29++%E6%B1%82%E8%AF%81AN%E2%88%A5%E5%B9%B3%E9%9D%A2MEC)
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