对所有实数x 、y ,若函数y=f(x),满足f(xy)=f(x)f(y),且f(0)不等于0,求f(2009)=( )别人说是:f(0) = f(0)*f(0) => f(0) = 1f(0) = f(0) * f(2009) = f(2009) = 1 可是2009和0不是应该还要满足x和y的关系式吗?
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![对所有实数x 、y ,若函数y=f(x),满足f(xy)=f(x)f(y),且f(0)不等于0,求f(2009)=( )别人说是:f(0) = f(0)*f(0) => f(0) = 1f(0) = f(0) * f(2009) = f(2009) = 1 可是2009和0不是应该还要满足x和y的关系式吗?](/uploads/image/z/5226538-58-8.jpg?t=%E5%AF%B9%E6%89%80%E6%9C%89%E5%AE%9E%E6%95%B0x+%E3%80%81y+%2C%E8%8B%A5%E5%87%BD%E6%95%B0y%3Df%28x%29%2C%E6%BB%A1%E8%B6%B3f%28xy%29%3Df%28x%29f%28y%29%2C%E4%B8%94f%280%29%E4%B8%8D%E7%AD%89%E4%BA%8E0%2C%E6%B1%82f%282009%29%3D%28+%29%E5%88%AB%E4%BA%BA%E8%AF%B4%E6%98%AF%EF%BC%9Af%280%29+%3D+f%280%29%2Af%280%29+%3D%3E+f%280%29+%3D+1f%280%29+%3D+f%280%29+%2A+f%282009%29+%3D+f%282009%29+%3D+1+%E5%8F%AF%E6%98%AF2009%E5%92%8C0%E4%B8%8D%E6%98%AF%E5%BA%94%E8%AF%A5%E8%BF%98%E8%A6%81%E6%BB%A1%E8%B6%B3x%E5%92%8Cy%E7%9A%84%E5%85%B3%E7%B3%BB%E5%BC%8F%E5%90%97%3F)
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对所有实数x 、y ,若函数y=f(x),满足f(xy)=f(x)f(y),且f(0)不等于0,求f(2009)=( )别人说是:f(0) = f(0)*f(0) => f(0) = 1f(0) = f(0) * f(2009) = f(2009) = 1 可是2009和0不是应该还要满足x和y的关系式吗?
对所有实数x 、y ,若函数y=f(x),满足f(xy)=f(x)f(y),且f(0)不等于0,求f(2009)=( )
别人说是:
f(0) = f(0)*f(0) => f(0) = 1
f(0) = f(0) * f(2009) = f(2009) = 1
可是2009和0不是应该还要满足x和y的关系式吗?
对所有实数x 、y ,若函数y=f(x),满足f(xy)=f(x)f(y),且f(0)不等于0,求f(2009)=( )别人说是:f(0) = f(0)*f(0) => f(0) = 1f(0) = f(0) * f(2009) = f(2009) = 1 可是2009和0不是应该还要满足x和y的关系式吗?
f(0) = f(0*2009)=f(0) * f(2009) = f(2009) = 1
f(1)=f(1)*f(1),所以f(1)=0或1,即这个题的所谓函数y=f(x)根本就不能成立,是个误导条件。
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f(1)=f(1)*f(1),所以f(1)=0或1,即这个题的所谓函数y=f(x)根本就不能成立,是个误导条件
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