(-a-c)²-4ac=0怎么解

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(-a-c)²-4ac=0怎么解
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(-a-c)²-4ac=0怎么解
(-a-c)²-4ac=0怎么解

(-a-c)²-4ac=0怎么解
(-a-c)²-4ac=0
(a+c)^2-4ac=0
(a-c)^2=0
a=c

(-a-c)²-4ac=0
a²+2ac+c²-4ac=0
(a-c)²=0
a=c

(-a-c)²-4ac=0
a^2+2ab+c^2-4ac=0
(a-c)^2=0
a-c=0
a=c

(-a-c)²-4ac=0
a²+2ac+c²-4ac=0
a²-2ac+c²=0
(a-c)²=0
a=c

展开得到
a^2+2ac+c^2-4ac=0
a^2-2ac+c^2=0
(a-c)^2=0
a=c

（-a)²+(-c)²+2[(-a)x(-c)]-4ac=0
a²+c²-2ac=0
(a-c)²=0
a=c