已知x=-3,y=1/3,求-x^2-(3/2x^2-1/3y)+(2/3-2x^2)
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/05 12:39:07
![已知x=-3,y=1/3,求-x^2-(3/2x^2-1/3y)+(2/3-2x^2)](/uploads/image/z/5235459-51-9.jpg?t=%E5%B7%B2%E7%9F%A5x%3D-3%2Cy%3D1%2F3%2C%E6%B1%82-x%5E2-%283%2F2x%5E2-1%2F3y%29%2B%282%2F3-2x%5E2%29)
xOK0
K~ͳm4i9
=+F^x
hL i{3f]M[
DJ`qw٣rIOUAH_oa
v;6qhyEo!yatu=8YZPTFJ2-/)N gvjBC@o\P>R,En>W 07^nٟ;z
已知x=-3,y=1/3,求-x^2-(3/2x^2-1/3y)+(2/3-2x^2)
已知x=-3,y=1/3,求-x^2-(3/2x^2-1/3y)+(2/3-2x^2)
已知x=-3,y=1/3,求-x^2-(3/2x^2-1/3y)+(2/3-2x^2)
原式=-x^2-3/2x^2+1/3y+2/3-2x^2
=-9/2x^2+1/3y+2/3
把x=-3,y=1/3带入
x^2=9
原式=-9/2*9+1/3*1/3+2/3
=-715/18
原式=-x^-3/2x^+1/3y+2/3-2x^
=-3x^-3/2x^+1/3y+2/3
=(-3-2/3)x^+1/3y+2/3
=-9/2*9+1/3*1/3+2/3
=-81/2+1/9+2/3
=-81/2+5/9
=-729/18+10/18
=-719/18
原式=-9/2*9+1/3*1/3+2/3
=-715/18