请问x-0.5y=1.2 2x+0.5y=4.8 x与y各是多少

请问x-0.5y=1.2 2x+0.5y=4.8 x与y各是多少 （x+3y)²-2（x-y)（x+y)+(x+y)²其x=0.5,y=-2 x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 A={（x,y)|y>=0.5|x-2|},B={(x,y)|y mathematica软件,已知y[x],Y=f1(x),X(x)=f2(x),如何plot Y[X]?y[x_] := x + 9.81/2*x*xk=1X[x] = x - k*y'[x]/(1 + (y'[x])^2)^0.5Y[x] = y[x] + k/(1 + (y'[x])^2)^0.5Plot[{y[x],Y[X],},{x,0,2}] 请问这样的方程组又如何用matlab求解呀?式子：[x,y,z]=solve('(2*x+3*y+z)^2*(x+y)*(1-z)/((1-x-y)*(2-0.5*x)^0.5*(1+3+1.5*x+2*y)^1.5)=3.46e+11','(2*x+3*y+z)^3*(x+y)*(1-z)/((1-x-y)*(1-y-z)^0.5*(1+3+1.5*x+2*y)^2)=0.966','(2*x+3*y+z)*(x+y)*z 请问这道数学题是否是这样做?x^2-y^2=(x-y)(x+y)(x-y)=(x-y)x+y=0 微分方程的一道题 y''(x+y'^2)=y'y''(x+y'^2)=y' 请问这道题如何计算, matlab画二元函数图像z = (x/(x+y) + 1.96*1.96/(2*(x+y)) - 1.96 * ((x/(x+y)*(1-x/(x+y))+1.96*1.96/(4*(x+y)))/(x+y))^0.5)/(1+1.96*1.96/(x+y))该怎么画 x-y=2 那么-2x-2y=多少[（2x=y)的平方-（2x+y)(2x-y)-y(5x+y)]/(0.5y),其中x-y=2 1/2x=0.5y则y/x()/(). 1/2x=0.5y则y/x()/(). (x-5y)(-x-5y)-(-x+5y)^2,其中x=0.5,y=-1.计算 (x-5y)(-x-5y)-(-x-5y)^2其中x=-1,y=-0.5 二元一次方程组 X-Y/7-X+Y=0.5 2(X-Y)+5(X+Y)=3 代数式恒等变形请问由a^(-y)=x-根(x^2-1)是如何变形得到x=0.5(a^y+a^(-y)) 请问S=max{2x+y , xy-[x+2y+0.5(x-4)*(y-2)]=24求x*y等于多少