(-x^2n-2)*(-x)^5÷[x^n+1*x^n*(-x)]=?

(-x^2n-2)*(-x)^5÷[x^n+1*x^n*(-x)]=? (-x^2n-2)(-x)^5÷[x^n+1·x^n`(-x)] (4x^n-2x^n-1-3x^n+2)÷（-5x^n-1) x^(n)*x^(n+1)+x^(2n)*x x^n-1(3x^n+4x^n+1-5x^n+2) x^m÷x^n=x^m*x^n,求7（2n-1）^5 若x^m÷x^n=x^m×x^n,求7(2n-1)^5的值 (-x)^3x^n-1+x^2n(-x)^3 已知集合P={x|x=2n,n∈N^+},集合Q={x|x=3n,n∈N*}.则P∩Q等于多少?,A,{x|x=n,n∈N*}B.{x|x=5n,n∈N*}C,{x|x=12n,n∈N*}D,{x|x=6n,n∈N*} 求和:1+x+x^2+.+x^n 1+x+x(x+1)+x(x+1)^2+.+x(x+1)^n (n为整数) x^n*x^n+1*(-x)^2n*x+(-x)^2n+3x^2n-2*x 因式分解：(x^n+1)+(2x^n)+(x^n-1) x^n+1-2x^n+x^n-1因式分解 x^n-1-2x^n+x^n-1因式分解 分解因式x^n-x^(n-1)+x^(n-2) (x^4n/x^2n)*x^n 约分(x^n+2)+(x^n+1)-6x^n/(2x^n+1)+5x^n-(3x^n-1)