作业帮2(x2-xy)-3(2x2-3xy)-2[x2-(2x2-xy+y2)] 化简.
来源：学生作业帮助网 编辑：作业帮 时间：2024/06/28 09:55:55
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2(x2-xy)-3(2x2-3xy)-2[x2-(2x2-xy+y2)] 化简.
2(x2-xy)-3(2x2-3xy)-2[x2-(2x2-xy+y2)] 化简.
2(x2-xy)-3(2x2-3xy)-2[x2-(2x2-xy+y2)] 化简.
2(x2-xy)-3(2x2-3xy)-2[x2-(2x2-xy+y2)]
=2x2-2xy-6x2+9xy-2(-x2+xy-y2)
=-4x^2+7xy+2x^2-2xy+2y^2
= -2x^2+5xy+2y^2
2(x2-xy)-3(2x2-3xy)-2[x2-(2x2-xy+y2)] 化简.
2(x-xy)-3(2x2-3xy）2[x2（2x2-xy+y2)]
(3xy-9x2-2y2-6xy)-(6x2+2xy-3xy-y)
4x2-3y2+2xy-4x2+5x2
已知x2+xy=3,xy+y2=-2,则2x2-xy-3y2=
求证:(x2-xy+y2)3+(x2+xy+y2)3能被2x2+2y2整除
已知x2-3xy=-5,xy+y2=3,求x2-2xy+y2.
若X2+xy-2y2=0,则（x2+3xy+y2)/x2+y2=?
2x2-xy+3y2因式分解
x2 y2+3xy+2 因式分解
x2-3y2=2xy过程
2X2-3XY-Y2分解因式!
4x2+3xy-2y2因式分解
-（x2-2xy-y2)+(5x2-2xy-3y2)-（x2-2xy-y2)+(5x2-2xy-3y2)化简
计算：(xy-x2)÷xy分之x2-2xy+y2
多项式x2-3xy+2y2-2加上( )等于5x2-7xy-3y2
(2x2-3xy+4y2)+(x2+2xy-3y2）化简（要有过程）
解方程组 x2 -2xy -y2 =1 2x2 -5xy -3y2 =0