sin^2(π/3-x)+sin^2(π/6+x)
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sin^2(π/3-x)+sin^2(π/6+x)
sin^2(π/3-x)+sin^2(π/6+x)
sin^2(π/3-x)+sin^2(π/6+x)
解
sin²(π/3-x)+sin²(π/6+x)
=sin²[π/2-(π/6+x)]+sin²(π/6+x)
=cos²(π/6+x)+sin²(π/6+x)
=1
利用sin²a+cos²a=1
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