△ABC中,A、B坐标分别为(-2,0),(2,0),C在x轴上方.(1)若角ACB为45度,求角ABC外接圆方程.(2)若在给定直线y=x+t上任取一点P,从点P向(1)中的圆引一条切线,切点为Q,问:是否存在定点M,使PQ=PM?请说明理由
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/10 12:27:03
![△ABC中,A、B坐标分别为(-2,0),(2,0),C在x轴上方.(1)若角ACB为45度,求角ABC外接圆方程.(2)若在给定直线y=x+t上任取一点P,从点P向(1)中的圆引一条切线,切点为Q,问:是否存在定点M,使PQ=PM?请说明理由](/uploads/image/z/5324486-14-6.jpg?t=%E2%96%B3ABC%E4%B8%AD%2CA%E3%80%81B%E5%9D%90%E6%A0%87%E5%88%86%E5%88%AB%E4%B8%BA%28-2%2C0%29%2C%282%2C0%29%2CC%E5%9C%A8x%E8%BD%B4%E4%B8%8A%E6%96%B9.%281%29%E8%8B%A5%E8%A7%92ACB%E4%B8%BA45%E5%BA%A6%2C%E6%B1%82%E8%A7%92ABC%E5%A4%96%E6%8E%A5%E5%9C%86%E6%96%B9%E7%A8%8B.%282%29%E8%8B%A5%E5%9C%A8%E7%BB%99%E5%AE%9A%E7%9B%B4%E7%BA%BFy%3Dx%2Bt%E4%B8%8A%E4%BB%BB%E5%8F%96%E4%B8%80%E7%82%B9P%2C%E4%BB%8E%E7%82%B9P%E5%90%91%281%29%E4%B8%AD%E7%9A%84%E5%9C%86%E5%BC%95%E4%B8%80%E6%9D%A1%E5%88%87%E7%BA%BF%2C%E5%88%87%E7%82%B9%E4%B8%BAQ%2C%E9%97%AE%EF%BC%9A%E6%98%AF%E5%90%A6%E5%AD%98%E5%9C%A8%E5%AE%9A%E7%82%B9M%2C%E4%BD%BFPQ%3DPM%3F%E8%AF%B7%E8%AF%B4%E6%98%8E%E7%90%86%E7%94%B1)
xX[SZY+Tu 9{G2j&؉55` 'rQ/9̷$$=yN^[NG>oe[K4L?rܭX.ިqZ-jY2
G^:kIo˯j7g5+D
zm7'$ة[\U)}eKq雓NW@m4ZgCZ馶^bKl
zv4J'F鵶/Mˇ=lWm÷{~v}Vz=umҲQЋ)]Ӄ do3@O߾^Wݸq'y+`,JpFSnt+])>glckߝfw3$P
bQezDgYt A
Ηir3Jv{|pWY+5k H 7HP@#+Is>l1vǠ^ G}%A+tINqGBi$ӍZ,<$ѳQBVĖKˬtt+ l+εPxdw}/ _!~7fKX߽?bc?Ztw0oo.IFHmd=_