求值:[log6(3)]^2+log6(18)/log2(6)很着急.我已经知道演算的过程,想知道第三部为什么+[log6(2)]^2要有(乘)变为(加),而且为什么要将它平方?[log6(3)]^2+log6(18)/log2(6)=[log6(3)]^2+log6(3^2 * 2)*[log6(2)]=[log6(
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![求值:[log6(3)]^2+log6(18)/log2(6)很着急.我已经知道演算的过程,想知道第三部为什么+[log6(2)]^2要有(乘)变为(加),而且为什么要将它平方?[log6(3)]^2+log6(18)/log2(6)=[log6(3)]^2+log6(3^2 * 2)*[log6(2)]=[log6(](/uploads/image/z/5374340-44-0.jpg?t=%E6%B1%82%E5%80%BC%EF%BC%9A%5Blog6%283%29%5D%5E2%2Blog6%2818%29%2Flog2%286%29%E5%BE%88%E7%9D%80%E6%80%A5.%E6%88%91%E5%B7%B2%E7%BB%8F%E7%9F%A5%E9%81%93%E6%BC%94%E7%AE%97%E7%9A%84%E8%BF%87%E7%A8%8B%2C%E6%83%B3%E7%9F%A5%E9%81%93%E7%AC%AC%E4%B8%89%E9%83%A8%E4%B8%BA%E4%BB%80%E4%B9%88%2B%5Blog6%282%29%5D%5E2%E8%A6%81%E6%9C%89%EF%BC%88%E4%B9%98%EF%BC%89%E5%8F%98%E4%B8%BA%EF%BC%88%E5%8A%A0%EF%BC%89%2C%E8%80%8C%E4%B8%94%E4%B8%BA%E4%BB%80%E4%B9%88%E8%A6%81%E5%B0%86%E5%AE%83%E5%B9%B3%E6%96%B9%3F%5Blog6%283%29%5D%5E2%2Blog6%2818%29%2Flog2%286%29%3D%5Blog6%283%29%5D%5E2%2Blog6%283%5E2+%2A+2%29%2A%5Blog6%282%29%5D%3D%5Blog6%28)
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求值:[log6(3)]^2+log6(18)/log2(6)很着急.我已经知道演算的过程,想知道第三部为什么+[log6(2)]^2要有(乘)变为(加),而且为什么要将它平方?[log6(3)]^2+log6(18)/log2(6)=[log6(3)]^2+log6(3^2 * 2)*[log6(2)]=[log6(
求值:[log6(3)]^2+log6(18)/log2(6)很着急.
我已经知道演算的过程,想知道第三部为什么+[log6(2)]^2要有(乘)变为(加),而且为什么要将它平方?
[log6(3)]^2+log6(18)/log2(6)
=[log6(3)]^2+log6(3^2 * 2)*[log6(2)]
=[log6(3)]^2+2log6(3)log6(2)
=[log6(3)+log6(2)]^2
=[log6(3*2)]^2
=1
求值:[log6(3)]^2+log6(18)/log2(6)很着急.我已经知道演算的过程,想知道第三部为什么+[log6(2)]^2要有(乘)变为(加),而且为什么要将它平方?[log6(3)]^2+log6(18)/log2(6)=[log6(3)]^2+log6(3^2 * 2)*[log6(2)]=[log6(
[log6(3)]^2+log6(18)/log2(6)
=[log6(3)]^2+log6(3^2 * 2)*[log6(2)]
=[log6(3)]^2+2log6(3)log6(2)+[log6(2)]^2
=[log6(3)+log6(2)]^2
=[log6(3*2)]^2
=1
第三步少了【log6(2)】^2
求值:log6^3+log6^2=log6^6为什么?
求值:[log6(3)]^2+log6(18)/log2(6)[log6(3)]^2+log6(18)/log2(6)
(log6 2)^2+log6 3*log6 12
(log6^2)^2+(log6^3)*(log6^4)+(log6^3)^2
(log6 3)^2+log6 2+log6 2log6 3=?
[(1-log6 3)^2+log6 2-log6 18]/log6 4
求值:(log6 2)²+log6 3*log 6 2+log6 3,应该怎么算?
(log6^4)(log6^18)+2(log6^3)^2
(log6 3)^2+log6 18乘以log6 2急求!!!!!!!!!!!!!!
log6 2=a log6 3=?
求值:[log6(3)]^2+log6(18)/log2(6)很着急.我已经知道演算的过程,想知道第三部为什么+[log6(2)]^2要有(乘)变为(加),而且为什么要将它平方?[log6(3)]^2+log6(18)/log2(6)=[log6(3)]^2+log6(3^2 * 2)*[log6(2)]=[log6(
(log6(2))^2+log6(2)*log6(3)+log6(18)的值
{(1-log6 3)^2+log6 2*log6 18}/log6 4 等于多少,请写出就算过程,
((1-log6(3))²+log6(2)*log6(18))/log6(4)
[(1-log6 3)²+log6 2×log6 18]/log6 4
2^log4(2-根号3)^2+3^log(2+根号3)^2[(1-log6(3)^2+log6(2)*log6(18)]/log6(4)[(1-log6(3))^2+log6(2)*log6(18)]/log6(4)
计算 (Log6 3)^2+【(log6 18)/(log2 6)]
计算[log6(3)]^2+log6(18)/log2(6)